Answer:
bearing of A from C is - 65.24°
the distance |BC| is 187.84 m
Step-by-step explanation:
given data
girl walks AB = 285 m (side c)
bearing angle B = 78°
girl walks AC = 307 m (side a)
solution
we use here the Cosine Law for getting side b that is
ac² = ab² + bc² - 2 × ab × cos(B) ...............1
307² = 285² + x² - 2 × 285 cos(78)
x = 187.84 m
and
now we get here angle θ , the bearing from A to C get by law of sines
sin (θ) =
sin (θ) = 0.5985
θ = 36.76°
and as we get here angle BAC that is
angle BCA = 180 - ( 36.76° + 78° )
angle BCA = 65.24°
and here negative bearing of A from C so - 65.24°
Answer:
The answer is 3 3/4
Step-by-step explanation:
First, you have to find a common denominator. 4 and 6 both can first into 12, so 12 is the common denominator. Then you subtract.
Answer:
f(x)=6
Step-by-step explanation:
3(-4)/2+(-4)
-12/-2
f(x)=6
Well! See ,If the endpoints are (x1,y1) & (x2,y2) then mid-point is given by (x1+x2)/2,
(y1+y2)/2
Here in this question endpoints given for the line segment are (-4,2) , (2,4) so we have to find mid-point for x and y co-ordinates by applying above rule.
So, the mid-point we get is (-4+2)/2 , (2+4)/2.
i.e. (-1,3) which lies in 2nd Co-ordinate!
Hope it helps!!