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Amiraneli [1.4K]
3 years ago
12

x + 17 =193 is the question and the assignment is called Solving 1 step equations using Addition and Subtraction.

Mathematics
2 answers:
Marat540 [252]3 years ago
7 0

Answer:

x=176

Step-by-step explanation:

In order to find this, you would subtract 17 from 193, which gives you 176 as your answer.

vitfil [10]3 years ago
3 0
The answer is x= 176
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Colin stacks 3 snowballs on top of each other to make a snowman. The snowballs are 7/10 meter, 1/2meter, and 38 centimeters tall
NeX [460]

Answer:

158cm

Step-by-step explanation:

Data obtained from the question. This includes:

Height of first snow ball (H1) = 7/10m

Height of 2nd snow ball (H2) = 1/2m

Height of 3rd snow ball (H3) = 38cm

Total height of snow man (HT) =?

Next we shall covert from m to cm.

This is illustrated below:

For the first snow ball

1m = 100cm

7/10m = 7/10 x 100 = 70cm

For the 2nd snow ball:

1m = 100cm

1/2m = 1/2 x 100 = 50cm

Now we can obtain the height of the snow man as follow:

Height of first snow ball (H1) = 70cm

Height of 2nd snow ball (H2) = 50cm

Height of 3rd snow ball (H3) = 38cm

Total height of snow man (HT) =?

HT = H1 + H2 + H3

HT = 70 + 50 + 38

HT = 158cm

Therefore the height of the snow man in cm is 158cm

3 0
4 years ago
Factor the expression. 16j2 + 24j + 9
rjkz [21]

Option C: (4 j+3)^{2} is the correct answer.

Explanation:

The given expression is 16 j^{2}+24 j+9

We need to factor the expression.

Let us rewrite the expression as

(4j)^{2}+24 j+(3)^2

Also, we can rewrite the term 24j as 2(4)(3)j

Thus, we have,

(4j)^{2}+2(4j)(3)+(3)^2

Hence, the equation is of the form,

(a+b)^{2}=a^{2}+2 a b+b^{2}

where a=4 j and b=3

Hence, the factor of the expression can be written as (4 j+3)^{2}

Thus, the factored expression is (4 j+3)^{2}

Therefore, Option C is the correct answer.

6 0
4 years ago
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Answer:

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Step-by-step explanation:

It's just like subtracting

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3 years ago
Easy someone help asap
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Answer:

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Marizza181 [45]
D. 7

a constant is a term without any variables
6 0
3 years ago
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