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Bess [88]
2 years ago
6

Please answer this. (its easy)

Mathematics
2 answers:
elixir [45]2 years ago
5 0

Answer:

x = 29

y = 93

Step-by-step explanation:

Angles 1 and 3 are vertical angles and congruent.

3x = 87

x = 29

Angles 2 and 3 are a linear pair and supplementary, so their measure have a sum of 180°.

y + 87 = 180

y = 93

lawyer [7]2 years ago
4 0

Answer:

x = 29

y = 93

Hoped this helped

Step-by-step explanation:

Please mark my answer as brainliest :D

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One gym charges a $50 sign up fee and $65 per month. Another gun charges a $90 sign up fee and $45 per month. Foe what number of
alina1380 [7]
2 months.
the equations are
65m+50 and 45m+90
you set them equal together
65m+50=45m+90 
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Step-by-step explanation:

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The diameter of a circle is 10 ft. Find the circumference to the nearest tenth to the nearest tenth. (Urgent)
Paul [167]

Answer:

31.42ft

Step-by-step explanation:

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radius = diameter ÷ 2

r = 10 ÷ 2

r= 5

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= 2(22÷7)(5)

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2 years ago
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Can someone help me pls
FrozenT [24]
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A = \frac{16  x  22}{2}
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3 years ago
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A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f
zaharov [31]

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time t

At t=0, the weight of the bucket is 6+36=42 \mathrm{lb}

After t seconds, the weight of the bucket is 42-0.15 t \mathrm{lb}

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after t seconds is x=1.5 t

Since the well is 80 ft deep, the time to pull out the bucket is \frac{80}{2}=40 \mathrm{~s}

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

W=\int_{t=0}^{t=36} F d x

Use x=1.5 t and F=42-0.15 t

W=\int_{0}^{36}(42-0.15 t)(1.5 d t)

=\int_{0}^{36} 63-0.225 t d t

=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}

=\left[63 t-0.2 t^{2}\right]_{0}^{36}

W=3200 \mathrm{ft} \cdot \mathrm{lb}

4 0
3 years ago
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