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vodka [1.7K]
3 years ago
10

To configure a router/modem, what type of IP interface configuration should you apply to the computer you are using to access th

e device administration web app?
Computers and Technology
1 answer:
krok68 [10]3 years ago
8 0

Answer:

You would temporarily assign it a fixed IP address in the same subnet as the router's default configuration.

Explanation:

If the router doesn't have DHCP enabled yet, your computer will not get an IP address, so you cannot communicate with it.

You might be interested in
What is distribution hardware?
saveliy_v [14]
A distributed computer system consists of multiple software components that are on multiple computers, but run as a single system. The computers that are in a distributed system can be physically close together and connected by a local network, or they can be geographically distant and connected by a wide area network.
4 0
4 years ago
Help help help help help help
Shkiper50 [21]

Answer:

maybe overexposure???

Explanation:

6 0
2 years ago
Construct a class that will model a quadratic expression (ax^2 + bx + c). In addition to a constructor creating a quadratic expr
stich3 [128]

Answer:

Following are the code to this question:

#include <iostream>//header file

#include<math.h>//header file

using namespace std;

class Quadratic//defining a class Quadratic  

{

private:

double a,b,c;//defining a double variable

public:

Quadratic()//defining default constructor

{

a = 0;//assigning value 0  

b = 0;//assigning value 0  

c = 0;//assigning value 0  

}

Quadratic(double a, double b, double c)//defining a parameterized constructor  

{

this->a = a;//use this keyword to hold value in a variable

this->b = b;//use this keyword to hold value in b variable

this->c = c;//use this keyword to hold value in c variable

}

double getA() //defining a get method  

{

return a;//return value a

}

void setA(double a)//defining a set method to hold value in parameter

{

this->a = a;//assigning value in a variable

}

double getB() //defining a get method  

{

return b;//return value b

}

void setB(double b)//defining a set method to hold value in parameter  

{

this->b = b;//assigning value in b variable

}

double getC() //defining a get method

{

return c;//return value c

}

void setC(double c)//defining a set method to hold value in parameter

{

this->c = c;//assigning value in c variable

}

double Evaluate(double x)//defining a method Evaluate to hold value in parameter

{

return ((a*x*x)+(b*x)+c);//return evaluated value

}

double numberOfReal()//defining a method numberOfReal to calculates the real roots

{

return (b*b)-(4*a*c);//return real roots

}

void findroots()//defining a method findroots

{

double d=numberOfReal();//defining double variable to hold numberOfReal method value

if(d<0)//use if block to check value of d less than 0

cout<<"Equation has no real roots"<<endl;//print message

else

{

double r1=(-b+sqrt(numberOfReal()))/(2*a);//holding root value r1

double r2=(-b-sqrt(numberOfReal()))/(2*a);//holding root value r2

if(r1==r2)//defining if block to check r1 equal to r2

cout<<"Equation has one real root that is "<<r1<<endl;//print message with value

else//else block

cout<<"The equation has two real roots that are "<<r1<<" and "<<r2<<endl;////print message with value

}

}

void print()//defining a method print  

{

cout<< a << "x^2 + " << b << "x + " << c <<endl;//print Quadratic equation

}

};

int main()//defining main method  

{

Quadratic q(5,6,1);//creating Quadratic class object that calls parameterized constructor

q.print();//calling print method

cout<<q.numberOfReal()<<endl;//calling method numberOfReal that prints its value

q.findroots();//calling method findroots

cout<<q.Evaluate(-1);//calling method Evaluate that prints its value

return 0;

}

Output:

5x^2 + 6x + 1

16

The equation has two real roots that are -0.2 and -1

0

Explanation:

In the above code, a class "Quadratic" is declared, which is used to define a default and parameter constructor to holds its parameter value.

In the next step, the get and set method is defined that holds and returns the quadratic value, and "Evaluate, numberOfReal, findroots, and print" in the evaluate method a double variable is used as a parameter that returns evaluated value.

In the "numberOfReal" method it calculates the real roots and returns its value. In the "findroots" method a double variable "d" is declared that hold "numberOfReal" value,

and use a conditional statement to check its value, and in the print method, it prints the quadratic equation.

In the main method, the lass object it calls the parameterized constructor and other methods.

5 0
3 years ago
Which single OSPF network statement will correctly include all the interfaces on a device whose IP addresses only begin with a 1
tester [92]

Answer:

network 10.10.8.0 0.0.3.255 area 0

this will include all the interfaces on a device whose IP addresses only begin with a 10.10.8, 10.10.9, 10.10.10, or 10.10.11.

Explanation:

<em>show ip ospf interface </em>

<em>show ip ospf interface brief</em>

these commands are used to display the interfaces that have been enabled into local ospf . it also shows explanation about them by brief command mentioned above.

<em />

4 0
3 years ago
In which encryption strategy is the plaintext encrypted one character at a time and each encrypted character depends on that sin
Natasha_Volkova [10]

Answer:

Caesar cipher

Explanation:

In formation technology, cryptography or cryptology is a process of coding or encrypting information, using algorithms and input values in a network, where there is a present of a third party called adversaries or attackers.

There are different types of cryptography, namely, symmetric, assymmetric and hash cryptography.

Ciphers are algorithms used in cryptography to encode (encrypt) or decode (decrypt) information. An example of cipher is the Ceasar's cipher.

Ceasar cipher is a simple type of substitution cipher that encrpts plain text one character at a time and each coded character depends on the single character and a fixed distance value.

4 0
3 years ago
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