Answer:
a. engranaje 1 → engranaje 2 → engranaje 3 → engranaje 4
z1 = 10 z2 = 20 z3 =10 z4 = 20
b. n2 = 600 rpm, n3 = 1200 rpm, n4 = 600 rpm
la relacion de transmision = 2
Explanation:
where z1 = 10, z2 = 20, z3 = 10, z4 = 20
and n1 = 1200 rpm
n2 = n1 * z1/z2 = (1200 * 10)/ 20 = 600 rpm
n3 = n2 * z2/z3 = (600 * 20)/ 10 = 1200 rpm
n4 = n3 * z3/z4 = (1200 * 10)/ 20 = 600 rpm
la relacion de transmision = z2/z1 * z3/z2 * z4/z3
= 20/10 * 10/20 * 20/10 = 2 * 0.5 * 2 = 2
The answer is cyclin subunit
Answer: True
Explanation: Because anyone can post something and it can be non reliable
Answer:
0xFF.
Explanation:
The Register A of HSC12 is an 8-bit register.So the maximum value for 8 bit is 8 1's (11111111). So the decimal value for the maximum 8 bits is 255 but all the options given are in hexadecimal so among the given options only 0xFF has the value of 255 in decimal F=(1111)₂.So two F's make 8 bits and their decimal value is 255.
