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Dovator [93]
3 years ago
14

A squared+ b squared=????​

Mathematics
1 answer:
Degger [83]3 years ago
4 0

Answer:

<h2>a × a + b × b</h2>

<u>Step-by-step explanation:</u>

= a² + b²

= a × a + b × b

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The price of a shirt is $20.50, but you have a coupon that lowers the price by 40%. What is the price of the shirt after using t
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Answer:

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Step-by-step explanation:

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3 years ago
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According to records from 50 years, there is a 2/3 chance of June temperatures being above 80 F. Azul needs to find the probabil
Brrunno [24]

Record of june temperature of last 50 years

Probability of June temperature being above 80° F from last 50 years

                      =\frac{2}{3}

It means , out of 30 days ,there are  only 20 days , in which temperature is above 80°F.

⇒Probability that it will be above 80° F for 20 or more days this June

                =\frac{20+x}{30}  

where, x is the number of extra days after 20 days in month of june, when temperature is above 80°F.

Value of this Probability will be in between

                \frac{2}{3}\leq P \leq 1  

Now, what Azul wants

 To find the probability that it will be above 80° F for 20 or more days this June.

The Simulation given is

  ⇒There are 30 days in June. If we use a number cube with the numbers 1-6 and assign 1-4 as a temperature above 80° F and 5-6 as a temperature 80° F or below.

Total number of numbers on number cube ={1,2,3,4,5,6}

Favorable Outcome={1,2,3,4}=Temperature above 80° F

Temperature 80° F or below ={5,6}

⇒Probability of getting number {1,2,3,4} on the number cube when rolled once,that is Temperature above 80° F

        =\frac{4}{6}\\\\=\frac{2}{3}

⇒Probability of getting number {5,6} on the number cube when rolled once, that is Temperature 80° F or below

        =\frac{2}{6}\\\\=\frac{1}{3}

This is Incorrect Simulation, as there are chances that , there can be more than 20 days out of 30 days when Temperature goes above 80° F.But Here we have got Probability of temperature being above 80° F for 20 days only, not more than 20 days, which is =\frac{2}{3}

Not,a number

    \frac{2}{3}< \text{Probability} \leq 1.    

4 0
3 years ago
6,435,920,178 in expanded form
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3 years ago
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The length of a rectangle is shown below:
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Sorry if I get this wrong but if your trying to make a rectangle wouldn't it bc (-3,1) and (1,1)?

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2 years ago
Least to greatest 6 3/10,1 3/10, 1 3/11, -7 6/14, 5 3/10
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