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3 years ago

What is the median of 7,6,12,19,6,13,16,20,9

2 answers:

4 0

Hello,
First of all, you have to order the number from least to greatest:
7,6,12,19,6,13,16,20,9

6,6,7,9,12,13,16,19,20

We see that there are total 9 numbers. Median means that the middle number, so we separate 4 numbers into two groups
6,6,7,9
13,16,19,20. Now,we see that there is only one number which is 12. As a result, the median is 12. Hope it help!

OlgaM077 [116]3 years ago

3 0

Just find the middle of them

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Step-by-step explanation:

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2 years ago

Does the table below represent a proportional relationship?

Arturiano [62]

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3 years ago

What does 1,580÷25=I know the answer, I need to show how I got it.

ziro4ka [17]

$\begin{gathered} \sqrt[25]{1580} \\ 1\text{ and 15 cannot divide 25 therefore, we use the first three numbers to divide 25} \\ \frac{158}{25}\text{ = }6\text{ remainder 8} \\ \text{You have to carry that remainder which is 8 and combine it with the 0 in 1580.} \\ \frac{80}{25}\text{ = }3\text{ remainder 5} \\ The\text{ remainder 5 will also divide 25} \\ \frac{5}{25}=0.2 \\ The\text{ quotient values are 63 + 0.2 = 63.2} \end{gathered}$

4 0

11 months ago

A rectangle has a height of c^3+6c^2+2c and a width of c^2+1

Basile [38]

Answer:

$A = c^5+6c^4+3c^3+6c^2+2c$

Step-by-step explanation:

The dimensions of a rectangle are length and breadth/width

Here we are given height . Assuming it to be one of the side of the rectangle , we will do the further calculation

Hence one side is

side 1 = $c^2+1$

And the other side is

Side 2 = $c^3+6c^2+2c$

The area of rectangle = side 1 x side 2

$A= (c^2+1) \times (c^3+6c^2+2c)$

Distributing parenthesis

$=c^2c^3+c^2\cdot \:6c^2+c^2\cdot \:2c+1\cdot \:c^3+1\cdot \:6c^2+1\cdot \:2c$

$=c^3c^2+6c^2c^2+2c^2c+1\cdot \:c^3+1\cdot \:6c^2+1\cdot \:2c$

$=c^5+6c^4+2c^3+c^3+6c^2+2c$

adding similar terms

$c^5+6c^4+3c^3+6c^2+2c$

Hence Area is given by the above polynomial

5 0

3 years ago

The sum of a 3 digit number and a 1 digit number is 217. The product of the numbers is 642. If one number is between 200 and 225

algol [13]

Let, the numbers be "x" and "y". Consider "x" as the triple digit number.
Now, according to the question,
x + y = 217..........................equation (1)

x * y = 642............................equation (2)

Now,
Taking equation (2),
x * y = 642
y = 642 / x..................................equation (3)

Now, Taking equation (1),
$x+y=217$

Substituting the value of y from equation (3), we get,

$x+ \frac{642}{x} =217$

$\frac{x *x+642}{x} =217$

$x^{2} +642 =217*x$

$x^{2} +642 =217x$

$x^{2} +642-217x =0$

$x^{2} -217x+642 =0$

$x^{2} -3x-214x+642 =0$

$x(x-3)-214(x-3)=0$

$(x-3)(x-214)=0$

Using zero product property,
EITHER,
x - 3 = 0
x = 3
OR,
x - 214 = 0
x = 214
Since, "x" is the triple digit number, x = 214.
Now,
Taking equation (2),
x * y = 642
Substituting the value of "x" in the equation, we get,
(214) * y = 642
y = 642 / 214
y = 3

So, the numbers are 214 and 3.

5 0

3 years ago