Hello, First of all, you have to order the number from least to greatest: 7,6,12,19,6,13,16,20,9
6,6,7,9,12,13,16,19,20
We see that there are total 9 numbers. Median means that the middle number, so we separate 4 numbers into two groups 6,6,7,9 13,16,19,20. Now,we see that there is only one number which is 12. As a result, the median is 12. Hope it help!
You are deciding which is greater: 1/6 or 1/3.in this case, a smaller denominator (such as 3) produces a greater value.1/3 has a smaller denom. than does 1/6, so 1/3 is greater than 1/6.hailey played the game longer (1/3 hour).
3) Given that the variable is normally distributed and the sample is large, you determine the interval of confidence from:
x +/- Z(0.5) s/√n
Wehre Z(0.5) is the value of the probabilities over 5% (90% of confidence mean to subtract 10%, which is 5% for each side (tails) of the normal distribuition) and is taken from tables.
Z(0.5) = 0.3085
Then the inteval is
x +/- 0.385 *s /√n = 3.56 +/- 0.385 * 0.2/√45
3.56 +/- 0.011 = ( 3.549, 3.571). This is the answer.
