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3 years ago

solve for each variable i don’t need work shown just the answers please thank you very much i have 2 hours to get this done

Mathematics

1 answer:

ale4655 [162]3 years ago

3 0

Answer:

$(a)$

$x = 18.5$

$y = 22.5$

$(b)$

$x = 10$

Step-by-step explanation:

Solving (a):

7x - 19 and 3x + 14 are interior angles.

So:

$7x - 19 + 3x +14 = 180$

Collect like terms

$7x + 3x = 180 - 14 + 19$

$10x = 185$

$x = 18.5$

7x - 19 and 5y - 2 are equal angles --- corresponding angles

So:

$5y - 2 = 7x - 19$

Make 5y the subject

$5y = 7x - 19+2$

5y = 7x -17

Make y the subject

$y = \frac{1}{5} (7x - 17)$

Substitute $x = 18.5$

$y = \frac{1}{5} (7*18.5 - 17)$

$y = \frac{1}{5} (112.5)$

$y = 22.5$

Solving (b):

The triangle is right-angled.

So:

$5x + 3 + 2x + 17 + 90 = 180$

Collect Like Terms

$5x + 2x = 180 - 90 - 17-3$

$7x = 70$

$x = 10$

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3 years ago

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(3) 9604

Step-by-step explanation:

The (1 - α) % confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The margin of error in this interval is:

$MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The formula to compute the sample size is:

$\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}$

(1)

Given:

$\hat p = 0.50\\MOE=0.1\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use the z-table for the critical value.

Compute the value of n as follows:

$\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.1^{2}}\\=96.04\\\approx97$

Thus, the minimum sample size required is 97.

(2)

Given:

$\hat p = 0.50\\MOE=0.05\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use the z-table for the critical value.

Compute the value of n as follows:

$\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.05^{2}}\\=384.16\\\approx385$

Thus, the minimum sample size required is 385.

(3)

Given:

$\hat p = 0.50\\MOE=0.01\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use the z-table for the critical value.

Compute the value of n as follows:

$\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.01^{2}}\\=9604$

Thus, the minimum sample size required is 9604.

8 0

3 years ago