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wolverine [178]
3 years ago
11

You're given side AB with a length of 6 centimeters and side BC with a length of 5 centimeters. The measure of angle A is 30°. H

ow many
triangles can you construct using these measurements?
OA 0
OB 1
OC 2
OD. infinitely many
Mathematics
2 answers:
7nadin3 [17]3 years ago
8 0

Answer:

OD. Infinitely many.

Step-by-step explanation:

soldi70 [24.7K]3 years ago
3 0

Answer:

OC

Step-by-step explanation:

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Find a point on the curve y= x^2 that is closest to the point (18, 0).? Find a point on the curve y= x^2 that is closest to the
Phoenix [80]
You're trying to minimize the distance between the point (18,0) and an arbitrary point on the curve, (x,y)=(x,x^2).

The distance between two such points is given by the function

d(x)=\sqrt{(x-18)^2+(x^2-0)^2}=\sqrt{x^4+x^2-36x+324}

so this is the function whose derivative you should check.

But before you do that, it's helpful to know that d(x) is minimized at the same point as the modified distance function d^*(x)=d^2(x)=x^4+x^2-36x+324.

Differentiating, you have

\frac{\mathrm d}{\mathrm dx}d^*(x)=4x^3+2x-36

Set this to zero and solve for the critical points.

4x^3+2x-36=2(2x^3+x-18)=0

You can use the rational root theorem to find some potential candidates for roots to the cubic. The constant term has factors \pm1,\pm2,\pm3,\pm6,\pm9,\pm18, while the leading coefficient has factors \pm1,\pm2. The only candidates for rational roots are \pm1,\pm\dfrac12,\pm2,\pm3,\pm\dfrac32,\pm6,\pm9,\pm\dfrac92,\pm18. The only one of these that works is 2, so x=2 is a root to the cubic above.

Polynomial division reveals that we can factor the cubic as

2(x-2)(2x^2+4x+9)=0

which has only one real root at x=2. Checking the value of the derivative of d^* to the left and right of this point confirms that a minimum occurs here.

Therefore the closest point on the curve to (18,0) is (2,4).
6 0
3 years ago
What is the volume of a sphere with a diameter of 7.7 ft, rounded to the nearest tenth
Scorpion4ik [409]

Step-by-step explanation:

V=4/3πr^3

V=4/3π(3.85)^3

V=4/3π(57.066625)

V=4/3 (179.280089865)

V=239.04011982

V=239 ft^3

8 0
3 years ago
Evaluate the following f(-2)+f(-3)=
8090 [49]
It would be =-5f
Hope this helps
7 0
3 years ago
Isolate f variable! Solve the equation algebraically! Show work!!<br><br> 42 = 6f
nikklg [1K]

Answer:

f=7

Step-by-step explanation:

42=6f

/6   /6

42/6=7

You divide 6 from 42, which leaves you with 7=f.

5 0
2 years ago
Find the area of the shaded region in the image below:
grandymaker [24]

9514 1404 393

Answer:

  34 square units.

Step-by-step explanation:

The figure can be decomposed into a trapezoid and a triangle. The point of intersection of the two lines is (6, 4), so a horizontal line at y=4 will create ...

  • a triangle of height 2 and base 6
  • a trapezoid with bases 6 and 8, and height 4.

Using the relevant area formulas, we find ...

  triangle area = 1/2bh = 1/2(6)(2) = 6

  trapezoid area = 1/2(b1 +b2)h = 1/2(6+8)(4) = 28

Total shaded area = 6 + 28 = 34 square units.

__

The equations of the lines can be written as ...

  y = -2x +16

  y = -1/3x +6

Equating y, we get

 -2x +16 = -1/3x +6

  10 = 5/3x . . . . . . . . . add 2x-6

  6 = x . . . . . . . . . multiply by 3/5

  y = -2(6) +16 = 4

The point of intersection is (6, 4).

_____

<em>Alternate solution</em>

Once we know the vertices of the shaded area:

  • (0, 0)
  • (0, 6)
  • (6, 4)
  • (8, 0)
  • (0, 0)

we can form pairwise "determinants" of the form x1y2 -x2y1. Note the first point is repeated at the bottom of the list, and the points are listed in order around the boundary of the area. The points (0, 0) contribute nothing, so we have left them out of the computation below. The area is half the absolute value of the sum of these "determinants".

  1/2|(0·4 -6·6) +(6·0)-(8·4)|

  = 1/2|-36 -32| = 1/2(68) = 34

_____

In the attachment, the equations of the lines are written in intercept form, since the problem statement gives the intercepts of the lines.

8 0
3 years ago
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