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kogti [31]
3 years ago
7

What percentage of his monthly budget does tyrone spend on car expenses

Mathematics
1 answer:
Masja [62]3 years ago
7 0
Divide the utility expense by the monthly budget. Multiply the result by 100.
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PLZ HELP DUE AT 12
aleksandrvk [35]

Answer:

The first one would be m^30n^20p^30  

And the second one would be a^2 / d^4  

Step-by-step explanation:

For 1, you have to multiply the inner exponents by the outer one so you get (m^12n^8) times (m^18n^12p^30). Then you mutiply the two together, so you add the exponents, where you get m^30n^20p^30.

For 2, since you're dividing, you have to subtract the exponents so you get a^2d^-4, but since you shouldn't have the negative you turn it into a^2 / d^4

Hope this helps :)

4 0
3 years ago
How many sides does the pentagon building in Washington, D.C. Have?
balu736 [363]
It has 5 sides.

                          Hope this helps:)
8 0
3 years ago
Read 2 more answers
Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute
valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

       = 3 - 1 = 2

d.f.D = N - k

        = 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust                      Jet red                 Cloudtran

$\overline X_1 =50.5$           $\overline X_2 =50.07143$        $\overline X_3 =55.71429$

$s_1^2=19.96154$      $s_2^2=14.68681$         $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

         $=\frac{51+51+...+49+49}{35}$

        = 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

     $=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

   $=\frac{127.1143}{2}$

   = 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

    $=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

   $=\frac{669.8571}{32}$

  = 20.93304

The F-test  statistics value is :

$F=\frac{s_B^2}{s_W^2}$

  $=\frac{63.55714}{20.93304}$

  = 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source       Sum of squares    d.f    Mean square    F

Between    127.1143                 2      63.55714          3.036212

Within        669.8571             32      20.93304

Total           796.9714            34

3 0
3 years ago
Can someone help with these two questions? dont worry if its wrong!
nevsk [136]

Answer:

<em><u>1</u></em><em><u>)</u></em><em><u>8</u></em><em><u>&</u></em><em><u>3</u></em><em><u>/</u></em><em><u>4</u></em><em><u> </u></em><em><u>CUP</u></em><em><u> </u></em><em><u>FLOUR</u></em>

<em><u>2</u></em><em><u>)</u></em><em><u>26</u></em><em><u> </u></em><em><u>KIDS</u></em><em><u> </u></em><em><u>CAN</u></em><em><u> </u></em><em><u>GO</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em>

Step-by-step explanation:

1) one batch=2 1/2 cup flour

therefore batch required in 3 1/2 batch= 5/2×7/2=35/4

=8&3/4cup flour

2)No. of kids can go for $60=8

therefore,no. of kids can go in $1=8/60

Therefore,no. of kids can go in $195=8/60×195=26 kids.

6 0
3 years ago
Read 2 more answers
Please find sin r please
LiRa [457]
Sin r = 20/29

SOHCAHTOA

R:
(O) opposite - 20
(A) adjacent - 21
(H) hypotenuse - 29
4 0
3 years ago
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