for the lines k (x) = (- 9 / 5) x + (5 / 2) and h (x) = (2 / 5) x - (7 / 6), the solution for x will be 5 / 3 and y will be - 1 / 2.
We are given the two lines:
k (x) = (- 9 / 5) x + (5 / 2)
h (x) = (2 / 5) x - (7 / 6)
At the intersection of the two lines, we get that:
(- 9 / 5) x + (5 / 2) = (2 / 5) x - (7 / 6)
(2 / 5) x + (9 / 5) x = (5 / 2) + (7 / 6)
(11 / 5) x = 11 / 3
3 x = 5
x = 5 / 3
y = (2 / 5) (5 / 3) - (7 / 6)
y = 2 / 3 - 7 / 6
y = - 1 / 2
Therefore, we get that, for the lines k (x) = (- 9 / 5) x + (5 / 2) and h (x) = (2 / 5) x - (7 / 6), the solution for x will be 5 / 3 and y will be - 1 / 2.
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F(x) = 6(9)^x
f(1/2) = 6(9)^(1/2)
f(1/2) = 6(9)^(0.5)
f(1/2) = 6*(9^0.5) 9^0.5 = √9 = +3 or -3.
f(1/2) = 6*3 = 18 or 6*-3 = -18
f(1/2) = 18 or -18
Hope this helps.
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