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Delvig [45]
3 years ago
14

Please help me with this question

Mathematics
1 answer:
Nat2105 [25]3 years ago
6 0

Answer:

Hey mate....

Step-by-step explanation:

This is your answer....

Yes, because a equilateral triangle has 3 equal angles. The 3 angles of a triangle equal 180°. So if the angles are all equal in an equilateral triangle, we do 60 times 3 which equals 180°.

hope it helps you,

Mark me as the brainliest.....

Follow me!

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Help!! Please please answer quickly and in the next 9 hours! <br><br> Solve these questions.
lutik1710 [3]

Answer:

Please refer to step-by-step.

Step-by-step explanation:

Let's solve all of these one at a time.

15. -2x - y = -5

To find the x-intercept, we need to equate the value of y to 0.

-2x - 0 = -5

\dfrac{-2x}{-2}=\dfrac{-5}{-2}

x=2.5

To find the y-intercept, we need to equate the value of x to 0.

-2(0) - y = -5

Now since we cannot have a negative value, we need to divide both sides by -1.

\dfrac{-y}{-1}=\dfrac{-5}{-1}

y=5

To find the slope form, we can simply transpose the value of -2x to the other sides of the equal sign.

-y = 2x - 5

Now we cannot have a negative value for the slope, we need to divide both sides by -1, leaving us with.

y = -2x + 5

16. 6x + 3y = -9

Let's start with the x-intercept.

6x + 3y = -9

6x + 3(0) = -9

\dfrac{6x}{6}=\dfrac{-9}{6}

x=1.5

Now we solve for the y-intercept.

6x + 3y = -9

6(0) + 3y = -9

\dfrac{3y}{3}=\dfrac{-9}{3}

y = -3

Now for the slope.

3y = -6x - 9

Now we need to divide all our variables by 3 to get y.

\dfrac{3y}{3}=\dfrac{-6x}{3}-\dfrac{9}{3}

y=-2x-3

17. x - y = 4

Let's start with the x-intercept.

x - y = 4

x - 0 = 4

x=4

Now we solve for the y-intercept.

x - y = 4

0 - y = 4

-y=4

\dfrac{-y}{-1}=\dfrac{4}{-1}

y = -4

Now for the slope.

x - y = 4

-y = -x + 4

We need to divide all our variables by -1 to get y.

\dfrac{-y}{-1}=\dfrac{-x}{-1}+\dfrac{4}{-1}

y=x-4

18. 3x + 4y = 12

Let's start with the x-intercept.

3x + 4y = 12

3x + 4(0) = 12

\dfrac{3x}{3}=\dfrac{12}{3}

x=4

Now we solve for the y-intercept.

3x + 4y = 12

3(0) + 4y = 12

\dfrac{4y}{4}=\dfrac{12}{4}

y = 3

Now for the slope.

3x + 4y = 12

4y = -3x + 12

\dfrac{4y}{4}=-\dfrac{3x}{4}+\dfrac{12}{4}

y=-\dfrac{3x}{4}+3

19. -7x + 2y = -16

Let's start with the x-intercept.

-7x + 2y = -16

-7x + 2(0) = -16

\dfrac{-7x}{-7}=\dfrac{-16}{-7}

x=-2\dfrac{2}{7}

Now we solve for the y-intercept.

-7x + 2y = -16

-7(0) + 2y = -16

\dfrac{2y}{2}=\dfrac{-16}{2}

y=-8

Now for the slope.

-7x + 2y = -16

2y = -7x - 16

\dfrac{2y}{2}=-\dfrac{7x}{2}-\dfrac{16}{2}

y=-\dfrac{7x}{2}-8

20. x - 5y = 55

Let's start with the x-intercept.

x - 5y = 55

x - 5(0) = 55

x = 55

Now we solve for the y-intercept.

x - 5y = 55

0 - 5y = 55

\dfrac{-5y}{-5}=\dfrac{55}{-5}

y=-11

Now for the slope.

x - 5y = 55

-5y = x + 55

\dfrac{-5y}{-5}=-\dfrac{x}{-5}+\dfrac{55}{-5}

y=-\dfrac{x}{5}-11

8 0
3 years ago
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