All categories

3 years ago

What is two factors of 20 that add up to 9???????????? i am really desperate sorry for bugging you

Mathematics

2 answers:

Snowcat [4.5K]3 years ago

5 0

The answer is 5 and 4

Paul [167]3 years ago

4 0

(X+4) (X=5) Because 4+5= 9 and 4X5=20

You might be interested in

If sin theta =3/7 and tan theta <0 what is the value of cos theta

Savatey [412]

Remember that

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}$

So if $\sin\theta>0$ and $\tan\theta$ , then we know $\cos\theta$ .

Then use the Pythagorean identity to solve for cosine:

$\cos^2\theta+\sin^2\theta=1\implies\cos\theta=-\sqrt{1-\sin^2\theta}=-\dfrac{2\sqrt{10}}7$

7 0

3 years ago

Miss lead says that if y varies directly with x and y=15 when x=-3, then y=-20 when x=4. Is she correct? Answer in complete sent

gizmo_the_mogwai [7]

Answer:

Yes, she is correct.

Step-by-step explanation:

y = kx is direct variation

15 = k*-3

k = -5.

So the equation of variation is

y = -5x

When x = -4:

y -5*-4 = 20.

6 0

2 years ago

How much boric is contained in 15 g of a 5% boric acid cream?

GREYUIT [131]

Answer:

.75 g

Step-by-step explanation:

If you have 15 g and 5% is boric then 15 *.05 =.75

8 0

3 years ago

Read 2 more answers

Find The Perimeter Of The Shaded Region 90 ft 58 ft 24 ft 38 ft

CaHeK987 [17]

L = 14 - 6 = 8
w = 15 - 4 = 11

P of shaded = 2(8+9) = 2 (19) = 38

answer
last one 38ft

8 0

3 years ago

Read 2 more answers

The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

3 years ago