let two integers be x and y
A.T.Q
x+y= -3
or, x= -3-y(i)
and xy= -18
or,(-3-y)y= -18[by(i)]
or,- -3y-y²= -18
or,-y²= -18+3
or, -y²= -15
or, y²=15
therefore y=✓15
from (i)
x= -3-✓15
y=√15
Answer:
1440 yd³
1200 yd³
Step-by-step explanation:
A local aquarium purchased a new turtle tank for their giant turtle exhibit for their giant turtle exhibit.
By using the dimensions 15yd by 12yd by 8yd and the shape of the tank is cubooid
We can determine volume by using the formula i.e
V = (Length) × (Width) × (Height),
then the volume of the tank will be
V = 15 × 12 × 8 =
V=1440 yd³.
Now , by using dimensions 15 yd by 8 yd by 10 yd
The volume will be,
V = 15 × 8 × 10 = 1200yd³
In the given statement above, in this case, the answer would be TRUE. It is true that the inequality x + 2y ≥ 3 is satisfied by point (1, 1). In order to prove this, we just have to plug in the values. 1 + 2(1) <span> ≥ 3
So the result is 1 + 2 </span> ≥ 3. 3 <span> ≥ 3, which makes it true, because it states that it is "more than or equal to", therefore, our answer is true. Hope this answer helps.</span>
Answer:
Rational
Integer
Whole
Real
Step-by-step explanation:
<u>Rational</u><u>:</u><u> </u>
The square root of 4 is 2, which is an integer (number without decimals). A number is only irrational if it has endless decimals after it.
<u>Integer</u><u>:</u>
A number without decimals
<u>Whole:</u>
A number without fractions; an integer.
<u>Real: </u>
Real numbers include whole numbers, rational numbers and irrational numbers- pretty much any number you can think of. The only numbers that ARENT considered real are imaginary numbers like √-1 and infinity.
Answer:
yes, the given relation is a function.
Step-by-step explanation:
The given relation is
{(–3, –2), (–1, 0), (1, 0), (5, –2)}
A relation is called function if each element of the domain is paired with exactly one element of the range.
It means for each value of x there exist a unique value of y.
In the given relation for each value of x there exist a unique value of y.
Therefore the required solution is yes and this relation is a function.
