Answer:

Step-by-step explanation:
This question is on rules of rational exponential
where the exponential is a fraction, you can re-write it using radicals where the denominator of the fraction becomes the index of the radical;
<u>General expression </u>
![a^\frac{1}{n} =\sqrt[n]{a}](https://tex.z-dn.net/?f=a%5E%5Cfrac%7B1%7D%7Bn%7D%20%3D%5Csqrt%5Bn%5D%7Ba%7D)
Thus ![\sqrt[3]{x} =x^\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%20%3Dx%5E%5Cfrac%7B1%7D%7B3%7D)
<u>Applying the same in the question </u>
![\sqrt[3]{x^5y} =x^\frac{5}{3} y^\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E5y%7D%20%3Dx%5E%5Cfrac%7B5%7D%7B3%7D%20y%5E%5Cfrac%7B1%7D%7B3%7D)
=
Answer:
co.: 14, -2, -5 var. terms: 14x,-2x,-5x con. terms: 9,8,1
Step-by-step explanation:
Step-by-step explanation:
(-6x +3y=9 )×4
( 10x+4y)×3
-24x +12y =36
30x+12y= -18
-24x+12y- (30x+12y)= 36-(-18)
-54x = 54
x= -1
by using 10x +4y = -6
apply x= -1
-10+4y= -6
4y= -6 +10
4y=4
y=1
so the answer is x=-1 and y= 1