All quadratic equations have 2 roots; they can be 2 real, different ones, or 2 real, identical ones, or 2 imaginary ones or 2 complex ones. You can tell immediatey from the discriminant b^2-4a(c):
If the D is +, you'll have 2 real, unequal roots;
If 0, you'll have 2 real, equal roots;
If the D is -, you'll have 2 complex or imaginary roots, different
Here a=2, b= -3 and c =5, so the discrim. is (-3)^2 - 4(2)(5) = 9-40 = -36.
Because the discrim. is -, you'll have 2 complex roots.
The answer must take into account that the order is irrelevant, that is that it is the same J, Q, K that Q, K, J, and K, J, Q and all the variations of those the three cards.
The number of ways you can draw 50 cards from 52 is 52*51*50*49*48*47*...4*3 (it ends in 3).
,
But the number of ways that those 50 cards form the same set repeats is 50! = 50*49*49*47*....3*2*1
So, the answer is (52*51*50*49*48*....*3) / (50*49*48*...*3*2*1) = (52*51) / 2 = 1,326.
Note that you obtain that same result when you use the formula for combinations of 50 cards taken from a set of 52 cards:
C(52,50) = 52! / [(50)! (52-50)!] = (52*51*50!) / [50! * 2!] = (52*51) / (2) = 1,326.
Answer: 1,326
Answer:
Step-by-step explanation:
It is false that All equations are identities, but not all identities are equations, as all identities are equations, but only some equations are identities.
Identities are equations that are true no matter what the values are substituted for the variables present in the equation.
For example:
,
are all identities.
And is an equation, but is not an identity.
Hence, The given statement is false.
Answer:
51
Step-by-step explanation:
I think the answer is 51 because you have to find the number between the first three to the middle
O to the power of 2 i think