The sign of f on the interval -5/3 is negative
<h3>How to determine the sign?</h3>
The function is given as:
f(x)=(2x−1)(3x+5)(x+1)
The zeros of the function are
x= -5/3, x= -1 and x= 1/2
Next, we plot the graph of the function
At x = -5/3, the function approaches negative infinity
This means that the sign of f on the interval -5/3 is negative
Read more about function intervals at:
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Answer:
The last one
Step-by-step explanation:
measure angle 2 and 6 to see if congruent
A. $14.99 .. do $49.98/2 = $24.99 and then subtract $10.
B. $19.99 .. do $49.98-19 = $39.98 and then divide it by 2.
M = (8-2)/(4-2) = 3
Therefore the slope is 3 (D).
Answer:
All of the above
Step-by-step explanation:
dy/dt = y/3 (18 − y)
0 = y/3 (18 − y)
y = 0 or 18
d²y/dt² = y/3 (-dy/dt) + (1/3 dy/dt) (18 − y)
d²y/dt² = dy/dt (-y/3 + 6 − y/3)
d²y/dt² = dy/dt (6 − 2y/3)
d²y/dt² = y/3 (18 − y) (6 − 2y/3)
0 = y/3 (18 − y) (6 − 2y/3)
y = 0, 9, 18
y" = 0 at y = 9 and changes signs from + to -, so y' is a maximum at y = 9.
y' and y" = 0 at y = 0 and y = 18, so those are both asymptotes / limiting values.
