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kondor19780726 [428]

2 years ago

10

If a letter was chosen at random from the word SPORTSMANSHIP, which of the following is closest to the probability that it would

be a vowel?

1 answer:

Gnom [1K]2 years ago

7 0

There are 3 vowels out of 13 letters
P(vowel) = 3/13

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Help!!!<br>Solve for h:<br><br>6.1h = 2.44

Anna007 [38]

Answer:

h=0.4

Step-by-step explanation:

6.1h=2.44

h=2.44/6.1

h=0.4

5 0

2 years ago

HELPP QUICK PLSSS The solution to a two-variable system is the point on a graph at which the lines cross

natali 33 [55]

Answer:

b. false, i think!

Step-by-step explanation:

4 0

2 years ago

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Determine the values of a, b, and c for the quadratic equation<br><br> 3x2−5x+6=0

sweet-ann [11.9K]

Answer:

The values of a, b, and c for the quadratic equation

a=3

b=-5

c=6

7 0

2 years ago

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You are serving bratwurst and hamburgers at your annual picnic. You want at least three bratwursts or hamburgers for each of you

Firlakuza [10]

1.3*3=3.90
3.90*35=136.50
136.50 is all you need to provide at least three of the most expensive items.
You still have 13.50 left over

6 0

3 years ago

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Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

7 0

3 years ago