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3 years ago

The final math hw please help me with it I have math today asap

Mathematics

1 answer:

hram777 [196]3 years ago

3 0

Answer:

A little lost what the numbers are supposed to minus?

Step-by-step explanation:

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A circle with area 3/2pi and central angle of 60 degrees. What is the area of the circle

Anika [276]

Answer:

28.28(simplified from 28.2743338834)

Step-by-step explanation:

area of sector= (center angle/360)*area of circle

we are already given the area of sector as 3/2pi

3/2pi=(60/360)*x

(x is area of circle)

3/2pi=4.71238898038

4.71238898038=1/6x

divide both sides by "1/6"

28.2743338834=x

hope this helps!

3 0

3 years ago

ΔDOG has coordinates D (3, 2), O (2, −4) and G (−1, −1). A translation maps point D to D' (2, 4). Find the coordinates of O' and

geniusboy [140]

Answer:

see explanation

Step-by-step explanation:

Given D(3, 2 ) → D'(2, 4 )

The x- coordinate of D' is 1 less than D and the y- coordinate of D' is 2 more than D, thus the translation rule is

(x, y ) → (x - 1, y + 2 )

Apply this rule to points O and G

O( 2, - 4 ) → O'(2 - 1, - 4 + 2 ) → O'(1, - 2 )

G(- 1, - 1 ) → G'(- 1 - 1, - 1 + 2 ) → G'(- 2, 1 )

6 0

3 years ago

The atmospheric pressure on an object decreases as altitude increases. If a is the height (in km) above sea level, then the pres

seraphim [82]

Answer:

373.8mmHg

Step-by-step explanation:

a =height (in km) above sea level,

the pressure P(a) (in mmHg) is approximated given as

P(a) = 760e–0.13a .

To determine the atmospheric pressure at 5.458 km, then we will input into the equation

P(5.458km) = 760e–0.13a .

= 760e^(-0.13×5.458)

=760e^-(0.70954)

= 760×0.4919

=373.8mmHg

Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg

3 0

3 years ago

Mr Taylor brought back 180 Euros to the UK. The exchange rate was €1.2 to £1.

solong [7]

The answer is £150.

This could be calculated using proportion. If £1 is €1.2, how many £ is €180:
£1 : €1.2 = x : <span>€180
</span>x = £1 ÷ €1.2 × <span>€180</span>
x = £150

6 0

3 years ago

What is the sum of an infinite geometric series if the first term is 156 and the common ratio is 2⁄3?

Zanzabum

Answer:

Step-by-step explanation:

We have

$a_1=156,\ r=\dfrac{2}{3}$

If |r| < 1, then the formula of a sum of an infinite geometric sequence is:

$S=\dfrac{a_1}{1-r}$

Substitute:

$S=\dfrac{156}{1-\frac{2}{3}}=\dfrac{156}{\frac{1}{3}}=156\cdot\dfrac{3}{1}=468$

4 0

3 years ago

The final math hw please help me with it I have math today asap​

The final math hw please help me with it I have math today asap