All categories

3 years ago

How many triangles can be constructed with sides measuring 6 cm, 2 cm, and 7 cm?

Mathematics

2 answers:

Katen [24]3 years ago

8 0

One i think i’m not sure tho

Vsevolod [243]3 years ago

4 0

One is the correct answer

You might be interested in

Which equation could have been used to create this graph

Temka [501]

Answer:

The answer is A

Hoped it helped <3 tell me if I am wrong

Step-by-step explanation:

4 0

3 years ago

Write and evaluate the expression. Then, select the correct answer. The sum of forty-five and a number; evaluate when n = 1. 1 4

Colt1911 [192]

The sum of forty-five and a number n is 46.1, and the expression that can represent this can be written "45+n" where the value of n is 1.1

<h3>What is an Expression?</h3>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The statement that is given to us is" the sum of forty-five and a number", therefore, the expression that will represent this can be written as,

45 + n,

Now, if the value of n is 1.1. Then the sum will be,

$45+n\\\\=45+1.1\\\\=46.1$

Hence, the sum of forty-five and a number n is 46.1, and the expression that can represent this can be written "45+n" where the value of n is 1.1

Learn more about Expression:

brainly.com/question/13947055

6 0

1 year ago

HELPPPP IMMEDIATELY....

lana [24]

First you do what is inside the parentheses. 10 x 5 - 3. 50 - 3 =47. Then you multiply 47 x 5 = 235.

3 0

2 years ago

Read 2 more answers

If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f

nikklg [1K]

The quadratic function given by:

$f(x)=a(x-h)^2+k, \ \ \ a\neq 0$

is in vertex form. The graph of $f$ is a parabola whose axis is the vertical line $x=h$ and whose vertex is the point $(h, k)$ . So:

To translate the graph of a function to the right, left, upward or downward we have:

$For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)$

By knowing this things, we can solve our problem as follows:

FIRST.

Translating 11 units to the left:

$g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2$

Then translating 5 units down:

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5$

Since the new function is fatter, the factor we need to multiply the term $(x+11)^2$ must be less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.