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natali 33 [55]
2 years ago
14

A. ASA Postulate B. HL Theorem C.AAS Theorem D. SAS Postulate

Mathematics
1 answer:
TiliK225 [7]2 years ago
4 0

Answer:

your answer will be <em><u>B. HL Theorem </u></em>

Step-by-step explanation:

hope it helps you...

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PLEASE HELP URGENT DUE IN 2 HOURS
Kaylis [27]

Answer:

look it up on slader.com thats the sams problem that i have had before and it worked on slader.

8 0
2 years ago
If 3x + 5y = 2 and 2x - 4y = 20, what is 5x - y?
gavmur [86]

Answer:

= 298/11

Step-by-step explanation:

3x + 5y = 2 | ×2 |

2x - 4y = 20 | ×3 |

6x + 10y = 4

6x - 12y = 60

____________--

22y = -56

y = -56/22

y = -28/11

3x + 5y = 2 | ×4 |

2x - 4y = 20 | ×5 |

12x + 20y = 8

10x - 20y = 100

_____________+

22x = 108

x = 108/22

x = 54/11

5x - y

= 5(54/11) - (-28/11)

= 270/11 + 28/11

= 298/11

8 0
3 years ago
4m^2-3m^6+5m^44m
mamaluj [8]
6th degree polynomial. You look at the largest value of the superscript
8 0
2 years ago
Read 2 more answers
What is the greatest common factor of 8 and 9
ExtremeBDS [4]

I believe the answer is 1. One is the only number that can go into both 8 and 9.

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2 years ago
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ANSWER ASAP ITS FOR FINALS
Roman55 [17]

Answer:

9. 66°

10. 44°

11. 2\sqrt{7}

12. 2\sqrt{3}

13. 27.3

14. 33.9

15. 22°

16. 24°

Step-by-step explanation:

9. Add 120 + 80 (equals 200) and subtract that from 360 (Because all angles in a quadrilteral add to 360°), this equals 160. Plug the same number in for both variables in the two other angle equations until the two angles add to 160. For shown work on #9, write:

120 + 80 = 200

360 - 200 = 160

12(5) + 6 = 66°

19(5) - 1 = 94°

94 + 66 = 160

10. Because the two sides are marked as congruent, the two angles are as well. This means the unlabeled angle is also 68°. The interior angles of a triangle always add to 180°, so add 68+68 (equals 136) and subtract that from 180, this equals 44. For shown work on #10, write:

68 x 2 = 136

180 - 136 = 44

11. Use the Pythagorean theorem (a² + b² = c²) (Make sure to plug in the hypotenuse for c). Solve the equation. For shown work on #10, write:

a² + b² = c²

a² + 6² = 8²

a² + 36 = 64

a² = 28

a = \sqrt{28}

a = 2\sqrt{7}

12. (Same steps as #11) Use the Pythagorean theorem (a² + b² = c²) (Make sure to plug in the hypotenuse for c). Solve the equation. For shown work on #11, write:

a² + b² = c²

a² + 2² = 4²

a² + 4 = 16

a² = 12

a = \sqrt{12}

a = 2\sqrt{3}

13. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #13, write:

Sin(47°) = \frac{20}{x}

x = 27.3

14. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #14, write:

Tan(62°) = \frac{x}{18}

x = 33.9

15. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #15, write:

cos(θ) = 52/56

θ = cos^-1 (0.93)

θ = 22°

16. (Same steps as #15) Use SOH CAH TOA and solve with a scientific calculator. For shown work on #16, write:

sin(θ) = 4/10

θ = sin^-1 (0.4)

θ = 24°

Good luck!!

8 0
2 years ago
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