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3 years ago

14

Please help me on this will give you brainliest!!

1 answer:

Alenkinab [10]3 years ago

6 0

Answer:

a) 1068 b)272

Step-by-step explanation:

For question a you would just add the two numbers together.

881+187=1068

For question b you would

-187+459=272

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Which of the following is an irrational number?

Sladkaya [172]

Answer:

1.333...

Step-by-step explanation:

because irrational numbers can be repeating decimals, numbers that aren't perfect squares,and numbers that can not be in fraction form.

4 0

3 years ago

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

Ugo [173]

Answer:

$Side\ B = 6.0$

$\alpha = 56.3$

$\theta = 93.7$

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with $\alpha, \beta, \theta$

[See Attachment for Triangle]

$A = 10cm$

$C = 12cm$

$\beta = 30$

What the question is to calculate the third length (Side B) and the other 2 angles ( $\alpha\ and\ \theta$ )

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

$B^2 = A^2 + C^2 - 2ABCos\beta$

Substitute: $A = 10$ , $C =12$ ; $\beta = 30$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30$

$B^2 = 100 + 144 - 240*0.86602540378$

$B^2 = 100 + 144 - 207.846096907$

$B^2 = 36.153903093$

Take Square root of both sides

$\sqrt{B^2} = \sqrt{36.153903093}$

$B = \sqrt{36.153903093}$

$B = 6.0128115797$

$B = 6.0$ <em>(Approximated)</em>

Calculating Angle $\alpha$

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute: $A = 10$ , $C =12$ ; $B = 6$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 180 - 144 *Cos\alpha$

Subtract 180 from both sides

$100 - 180 = 180 - 180 - 144 *Cos\alpha$

$-80 = - 144 *Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}$

$\frac{-80}{-144} = Cos\alpha$

$0.5555556 = Cos\alpha$

Take arccos of both sides

$Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)$

$Cos^{-1}(0.5555556) = \alpha$

$56.25098078 = \alpha$

$\alpha = 56.3$ <em>(Approximated)</em>

Calculating $\theta$

Sum of angles in a triangle = 180

Hence;

$\alpha + \beta + \theta = 180$

$30 + 56.3 + \theta = 180$

$86.3 + \theta = 180$

Make $\theta$ the subject of formula

$\theta = 180 - 86.3$

$\theta = 93.7$

5 0

3 years ago

What is -13,8,-5,3,-2,...

Minchanka [31]

What do you meen they are numbers

8 0

3 years ago

Brian needs to find the value of a number, a, so that when (x^2+3x) is added to the binomial (3x^2+ax), the sum simplifies to 4x

Julli [10]

Answer:

a = 9

Step-by-step explanation:

First we need to add (x^2+3x) to (3x^2+ax),

(x^2+3x)+(3x^2+ax)

Expand

= x^2+3x+3x^2+ax

Collect the like terms

= x^2+3x^2+3x+ax

= 4x^2 + 3x + ax

= 4x^2+(3+a)x

Equate the solution to 4x^2+12x

4x^2+(3+a)x = 4x^2+12x

Comparing the like terms on both sides

(3+a)x =12x

3 + a = 12

a = 12 - 3

a = 9

Hence the value of a is 9

6 0

3 years ago

Find The Value Of X.

Aleksandr-060686 [28]

Answer:

Tan 30 =, 14/x

Then x= 14/tan 30

So x=14 root 3

6 0

3 years ago