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zepelin [54]
3 years ago
9

Jeanie sells M&Ms out of her giant bag at 4 for 5 cents. The machine at the store sells you 9 for 25 cents. Which is the bet

ter deal for you? Show your work. ​
Mathematics
1 answer:
natima [27]3 years ago
3 0
If we take 4/5=80 cent each and when we take 9/25=36 cents a piece so the store is a better deal
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What is the exact value of the expression the square root 72. − the square root of 8. + the square root of 128.? Simplify if pos
ivann1987 [24]
Remember, the exact value cannot involve any rounding or estimates. Now, let's solve this problem. First, we have to translate it into an expression:

√72 - √8 + √128               separate the terms into square roots

√36·2 - √4·2 + √64·2        square root the terms that you can

6√2 - 2√2 + 8√2               they have like radical terms, so combine the terms

6 - 2 + 8 = 12                   the coefficients are 12 when combined

12√2                                 this is the EXACT VALUE of the expression

Hope this helps! 
3 0
4 years ago
Which terms could have a greatest common factor of 5m2n2?.
ozzi

Answer:

a common factor would be 5m^4n^3 or 15m^2n^2

Step-by-step explanation:

not sure what terms they want you to choose from but anything that starts with a number (5,10,15,) and "m" would any number 5 would go into

3 0
3 years ago
Can anyone help me with this?
egoroff_w [7]

Answer:nope but I’m bored so do I wanna talk

Step-by-step explanation:

6 0
3 years ago
B is located at (−5, 2).
Harman [31]

When (-5, 2) is reflected across the y-axis then it becomes (5, 2). When (-5, 2) is reflected across the x-axis, it becomes (-5, -2)

I hope this helps out!

6 0
3 years ago
Read 2 more answers
A function f is defined by f(x) = 1 + 6x + x2 + 6x3 + x4 + ⋯ that is, its coefficients are c2n = 1 and c2n + 1 = 6 for all n ≥ 0
Alenkinab [10]

From the odd-degree terms, take out one copy and rewrite the series as

1+6x+x^2+6x^3+\cdots=(1+x+x^2+x^3+\cdots)+5x+5x^3+\cdots

1+6x+x^2+6x^3+\cdots=(1+x+x^2+x^3+\cdots)+5x(1+x^2+\cdots)

Then if |<em>x</em>| < 1, we can condense this to

\displaystyle\sum_{n=0}^\infty x^n+5x\sum_{n=0}^\infty x^{2n}=\frac1{1-x}+\frac{5x}{1-x^2}=\frac{1+6x}{1-x^2}

Since the series we invoked here converge on -1 < <em>x</em> < 1, so does this one.

4 0
3 years ago
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