Answer:
800 in²
Step-by-step explanation:
Applying,
TSA (A) = Area of the base+ Lateral area of the
A = lw+1/2ps................ Equation 1
Where l = lenght of the base, w = width of the base, p = perimeter of the base, s = slight height of the base.
But,
p = 2(l+w)............. Equation 2
Substitute equation 2 into equation 1
A = lw+1/2[2(l+w)s)
A = lw+s(l+w)............. Equation 3
From the question,
Given: l = 16 in, w = 16 in, s = 17 in
Substitute these values into equation 3
A = (16×16)+17(16+16)
A = 256+544
A = 800 in²
Points equidistant from DE EF are in the bisector of angle DEF
points equidistant from EF DF are in the bisector of angle EFD
the sought after point is the intersection of bisectricess of triangle
Answer:
3
Step-by-step explanation:
(40/5)-7+2
PEMDAS says parentheses first, so divide inside the parentheses
(8)-7+2
Then add and subtract from left to right
1 +2
3
-2x = -1
x = 1/2
Any equation that returns x=1/2 is a solution to this problem. For example, x= (3•4)/6 can be simplified so that x=1/2
The time needed at 2 meters per second for both rounds would be 100/2 s or 50 seconds. For the first lane he already used 50/1.5 -> 33.33 seconds, so he would need to cover the other 50 meters in exactly 16.67. 50m divided by the 16.67 seconds he has left means he has to swim at a speed of 3 meters per second.
