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ziro4ka [17]
3 years ago
7

Big Bob weighs 350 pounds. After one month of dieting, he lost 5% of his original weight. During the second month of dieting, he

lost 10% of his new weight. Write an equation to demonstrate how much weight Big Bob lost in the two months, and solve.
Mathematics
1 answer:
aleksley [76]3 years ago
3 0
350-15%= 297.50 so he lost 15% in the 2months if u want to break it down further u can:
350- 5%= 332.25
332.25-10%= 299.00 ur choice and depends how far ur teacher wants u to break it down.
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notsponge [240]

Answer:

  8 square units

Step-by-step explanation:

The figure is a trapezoid. The area of it is given by the formula ...

  A = (1/2)(b1 +b2)h

where b1 and b2 are the lengths of the parallel bases and h is the distance between them.

Your figure shows the base lengths to be 5 and 3, and their separation to be 2. Filling the numbers in the formula, we have ...

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The area of the figure is 8 square units.

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4 0
3 years ago
Five thousand tickets are sold at​ $1 each for a charity raffle. Tickets are to be drawn at random and monetary prizes awarded a
aksik [14]

Answer:

the expected value of this raffle if you buy 1​ ticket = -0.65

Step-by-step explanation:

Given that :

Five thousand tickets are sold at​ $1 each for a charity raffle

Tickets are to be drawn at random and monetary prizes awarded as​ follows: 1 prize of ​$500​, 3 prizes of ​$300​, 5 prizes of ​$50​, and 20 prizes of​ $5.

Thus; the amount and the corresponding probability can be computed as:

Amount                            Probability

$500 -$1 = $499                1/5000

$300 -$1 = $299                3/5000

$50 - $1 = $49                     5/5000

$5 - $1 = $4                      20/5000

-$1                                   1- 29/5000 = 4971/5000

The expected value of the raffle if 1 ticket is being bought is  as follows:

E(x) = \sum x  * P(x)

E(x) = (499 * \dfrac{1}{5000} + 299 *\dfrac{3}{5000} + 49 *\dfrac{5}{5000} + 4 * \dfrac{20}{5000}  + (-1 * \dfrac{4971}{5000} ))

E(x) = (0.0998 + 0.1794+0.049 + 0.016  + (-0.9942 ))

E(x) = (0.3442 -0.9942 )

\mathbf{E(x) = -0.65}

Thus; the expected value of this raffle if you buy 1​ ticket = -0.65

7 0
3 years ago
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