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eimsori [14]
3 years ago
8

5. The data below shows the high temperature and coffee sales for the day.

Mathematics
1 answer:
mr Goodwill [35]3 years ago
7 0
The answer would be a
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Towing charge 30$ plus $3 per mile if I paid $117 how far was the car towed
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117 - 30 = 87

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The car was towed 29 miles

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White raven [17]
They will need to be it on day 250 because 500/2=250

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Geometry Simple:<br> Please solve i will be entering as shown work is helpful but not required!
Gelneren [198K]

I hope this helps you

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4 years ago
Diagram 5 shows a triangle ABD such that AD = 17 cm, AB = 10 cm and BD = 21 cm. The straight line AC is perpendicular to the str
OlgaM077 [116]

Answer:

8

Step-by-step explanation:

100 = x^2 + AC^2

17^2 = AC^2 + (21 - x)^2

289 = AC^2 + 21^2 + x^2 - 2*21*x

289 =<u> AC^2</u> + 441 +<u> x^2</u> - 42x

from 1st equation AC^2 + x^2 = 100

289 = 441 + 100 - 42x

289 = 541 - 42x

42x = 541 - 289 = 252

x = 252/42 = 6

so AC^2 = 100 - 6^2 = 100 - 36 = 64

AC = 8

7 0
3 years ago
Help. Please. Thank You.
GenaCL600 [577]

Answer:

(A)\ a=-6;b=4\\\\ (B)\ a=6;b=-4

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

y=mx+c

Where "m" is the slope and "c" is the y-intercept.

By definition:

1. If the lines of the System of equations are parallel (whrn they have the same slope), the system has No solutions.

2. If the they are the same exact line, the System of equations has Infinite solutions.

(A) Let's solve for "y" from the first equation:

3x-2y=-1\\\\-2y=-3x-1\\\\y=\frac{3}{2}x+\frac{1}{2}

You can notice that:

m=\frac{3}{2}\\\\c=\frac{1}{2}

In order make that the System has No solutions, the slopes must be the same, but the y-intercept must not. Then, the values of "a" and "b" can be:

a=-6\\\\b=4

Substituting those values into the second equation and solving for "y", you get:

-6x+4y=-2\\\\4y=6x-2\\\\y=\frac{6}{4}x-{2}{4}\\\\y=\frac{3}{2}x-\frac{1}{2}

You can idenfity that:

m=\frac{3}{2}\\\\c=-\frac{1}{2}

Therefore, they are parallel.

(B) In order make that the System has Infinite solutions, the slopes and the y-intercepts of both equations must be the same. Then, the values of "a" and "b" can be:

a=6\\\\b=-4

If you substitute those values into the second equation and then you solve for "y", you get:

6x+(-4y)=-2\\\\-4y=-6x-2\\\\y=\frac{-6}{-4}x-\frac{2}{-4}\\\\y=\frac{3}{2}x+\frac{1}{2}

You can identify that:

m=\frac{3}{2}\\\\b=\frac{1}{2}

Therefore, they are the same line.

3 0
4 years ago
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