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2 years ago

2) A circle has an area of 121 ñ cm. Find its circumference. (Round your answer to the

Mathematics

1 answer:

crimeas [40]2 years ago

7 0

Answer:

If the area is 121 cm the answer is 38.99 if its 12 cm then the answer is 12.28

Step-by-step explanation:

Im not sure if correct but i tried

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Square root of (20 - r) = r

Marrrta [24]

R=4 because 20-4 = 16 and 4 times 4 = 16

6 0

3 years ago

Find the exact value of x. Round to the nearest tenth.

Lena [83]

X = 25

a^2 + b^2 = c^2
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(Square root 617)
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7 0

2 years ago

(URGENT)Find the equation of the normal line to the curve below at the point (1, -2) in point slope form.

Rus_ich [418]

Answer:

Xmin:

-10

Xmax:

Ymin:

-10

Ymax

Step-by-step explanation:

4 0

2 years ago

To find the extreme values of a function f(x,y) on a curve xequalsx(t), yequalsy(t), treat f as a function of the single vari

pychu [463]

Answer:

Absolute maximum is 2

Absolute minimum at -2

Step-by-step explanation:

The given parametric functions are:

$x=2\cos t,y=2\sin t$

By the chain rule:

$f'(t)=\frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$\frac{df}{dt} =\frac{2 \cos t}{-2\sin t} =-\cot(t)$

At fixed points, $f'(t)=0$

$\implies -\cot (t)=0$

This gives $t=\frac{\pi}{2} ,\frac{3\pi}{2}$ on $0\le t\le 2\pi$

This implies that the extreme points are $(2\cos \frac{\pi}{2}, 2\sin \frac{\pi}{2})=(0,2)$ and $(2\cos \frac{3\pi}{2}, 2\sin \frac{3\pi}{2})=(0,-2)$

By eliminating the parameter, we have $x^2+y^2=4$

This is a circle with radius 2, centered at the origin.

Hence (0,2) is an absolute maximum ,at $t=\frac{\pi}{2}$ and (0,-2) is an absolute minimum at $t=\frac{3\pi}{2}$

7 0

2 years ago

Find the value of the trigonometric ratio.<br> 9) sin z

azamat

Answer:

SinZ=24/40 = 12/20 = 3/5

3 0

2 years ago