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xenn [34]
3 years ago
13

suddenly the number of math problems mathletes had to solve increased by 60%! to keep on track the mathletes try to go faster bu

t only increase their speed by 25% By what percent must the number of mathletes on the team increase so they can solve all the problems on time?
Mathematics
1 answer:
romanna [79]3 years ago
4 0

Answer:

28%

Step-by-step explanation:

Lets say the fraction of speed and problem solved is 100/100

the number of problems solved increases by 60%

so now it is 160/100, also the speed increases by 25%

so now we do 160/125=1.28

finaly we do 1.28-1 = 28%

Therefore the answer is 28%.

hope this helps

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Factor z^2+7z-18<br> what is the factor expression?
kobusy [5.1K]

Answer:

z²+7z-18=0.

z²+9z-2z-18=0.

(z²+9z)-(2z-18)=0.

z(z+9)-2(z+9)=0.

(z-2)(z+9)=0.

(z-2)=0 or (z+9)=0.

z-2=0 or z+9=0.

z=2 or z=-9.

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3 years ago
There is a bell at the top of a tower that is 45m high the bell has ___ energy
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Potential energy, though this seems like a question for the science section unless I'm missing something.
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Determine whether each question below is a statistical question. Write "yes" or "no" in the spaces provided.
nikdorinn [45]

Answer:

a yes

b no

c no

d yes

e yes

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7 0
4 years ago
Tracy has a cell phone plan that provides 250 free minutes each month for a flat rate of $29. For any minute of 250, Tracy is ch
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7 0
3 years ago
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Joe’s age is three times Aaron’s age and Aaron is six years older than Christina. If the sum of their ages is 149, what is Chris
Leno4ka [110]

<u>Answer</u>

If Christina's age is = x

Aaron's age is = x + 6

Jeo's age = 3(x + 6 )

So, the sum of their ages can be write as,

x + x + 6 + 3(x + 6) \\ x + x + 6 + 3x + 18 \\ 5x + 24

Also, they have given that the sum of their ages is 149

Therefore we can write a equation as,

5x + 24 = 149

Now let's solve this and find the age of Christina

5x + 24 = 149 \\ 5x = 149 - 24 \\ 5x =12 5 \\  \frac{5x}{5}  =  \frac{125}{5}  \\ x = 25

Aaron's age is

x+ 6 \\ 25 + 6 \\  = 31

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Hope this helps you.

Let me know if you have any other questions :-):-)

8 0
3 years ago
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