Ask question

Ask question

All categories

3 years ago

14

Over the next 12 months you have to read more than 72 books. You have to read x books per month. The inequality 12x >72 repre

sents this situation. Solve the inequality to find the number of books you have to read per month?

1 answer:

Lyrx [107]3 years ago

5 0

Answer:

6 books per month

Step-by-step explanation:

books:months=books per month

You might be interested in

se technology to solve 4x−11=3.2x+13. Enter the solutions in the boxes. Write the lesser solution first. Round to the nearest te

Zielflug [23.3K]

Answer: x=30

Step-by-step explanation: if you were looking for the value of x, hope this helps!

first, you have to make sure that the correct values are on the right side to allow us to find the answer faster and easier. your modified formula should look like this: 4x-3.2x=11+13

if you do the operations on each side, it will look like this: 0.8x=24, from here, all you have to do now is divide 24 by 0.8 to get the X value, which will result in 30!

8 0

3 years ago

Is 8.012 greater than 8.03

morpeh [17]

Answer: No, 8.03 is greater than 8.012

8 0

2 years ago

Read 2 more answers

Prove the trigonometric identity

Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

$1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1$

Lets solve the bottom most part first:

$1-\frac{1}{1-sec^2x} \\\\$

Take LCM

$1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}$

now break the LCM

$\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1$

because 1/tan = cot x

and furthermore,

$cot^2x+1\\cosec^2x$

now we solve the above part and replace the bottom most part that we solved with $cosec^2x$

$\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x$

Hence proved! :D

4 0

3 years ago

Pleaseee help with this question!!

Grace [21]

Answer: angle JKG= 26

8 0

2 years ago

What is first three common multiples of 4,9,and 12

wel

Answer:

36 is the answer of this question

4 0

2 years ago

Read 2 more answers