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mr_godi [17]
3 years ago
12

Solve 5-3^x=-40 round to the nearest ten-thousandth

Mathematics
2 answers:
Art [367]3 years ago
8 0

Answer:

x=3.4650

Step-by-step explanation:

5-3^x=-40

Solve the equation for x

First make the exponent alone, Subtract 5 from both sides

-3^x= -45

Divide both sides by -1

3^x=45

To solve for x , we write the equation in log form

x=b^y can be written as y=log_b(x) in log form

3^x=45 can be written as log_3(45)= x

So, x= 3.46497 (Round to nearest ten thousandth)

x=3.4650

solong [7]3 years ago
4 0

5-3^x = -40

 subtract 5 from each side to get

-3^x=-45

 divide both sides by -1 to make them positive

3^x = 45

need to do the natural logarithm on both sides to remove the variable from the exponent

 so ln(3^x) = ln(45)

 use logarithm rule to move x out

x ln (3) = ln(45)

 dive each term by ln(3) then simplify to get

ln(3)/ln(45)

 so x = ln(3)/ln(45) which calculates out to 3.46497352

round off to ten thousandths is 3.4650

 

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