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3 years ago

The area of a rug is represented by the following expression, z2 + 4x – 12 , which of the following expressions

Mathematics

1 answer:

ch4aika [34]3 years ago

3 0

Answer:

Width = (x-2)

Step-by-step explanation:

The area of a rug is given by $(x^2+4x-12)$

The length of the rug is (x+6)

We need to find the width of the rug.

The area of a rug is given by :

$A=lb\\\\x^2+4x-12=(x+6)b\\\\b=\dfrac{x^2+4x-12}{(x+6)}\\\\b=\dfrac{x^2+6x-2x-12}{(x+6)}\\\\b=\dfrac{x(x+6)-2(x+6)}{(x+6)}\\\\b=\dfrac{(x+6)(x-2)}{(x+6)}\\\\b=(x-2)$

So, the width of the rug is (x-2). Hence, the correct option is (c).

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Hey if you see this i really need your help its an exam thanks

professor190 [17]

Answer:

I think it is Letter B

Because I add the two

L-2, +N 12=10

7 0

3 years ago

Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm

Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 6, \sigma = 0.2$

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6-6}{0.2}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X 5.8.

X = 6.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

X = 5.8

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8-6}{0.2}$