Step-by-step explanation:
by Pythagoras theorem:
perpendicular² + base²= hypotenuse²
(1/√2)²+ (1/√3)² = H²
1/2+1/3= H²
5/6 = H²
√(5/6 )= H
√5/√6 = H
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The area of the square is 81 sq in, and the area of the circule is (3.14)(3 in)^2, or approx 3.14(9) sq in, or approx 28.27 sq in.
Subtract: 81 sq in - 28.27 sq in = approx. 52.73 sq in.
The difference is 52.73 sq in; the square is larger, the circle smaller.
You just have to divide the decimals
Multiplying by 2 and then adding 10 145*2=290+10=300
300*2=600+10=610
610*2=1220 + 10=1230
x=2 y=10
x+y=12
Sorry it took so long, here is your answer:
