A triangle has vertices on the coordinate grid at points D (3, -3), E (0,2), and F (-1,-3)

Mathematics

1 answer:

lana [24]3 years ago

7 0

Answer:

4 units

Step-by-step explanation:

A triangle has vertices on the coordinate grid at points D (3, -3), E (0, 2), and F (-1, -3). What is the length, in units, of DF ?

A triangle is a polygon with three sides and three angles.

The distance between two points $(x_1,y_1)\ and\ (x_2,y_2)$ on the coordinate plane is given by:

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given A triangle with vertices at points D (3, -3), E (0, 2), and F (-1, -3). The length of side DF is given as:

$DF=\sqrt{(-1-3)^2+(-3-(-3))^2}=4\ units$

You might be interested in

Given the directrix of y = -1 and focus of (0, 3), which is the equation of the parabola?

guajiro [1.7K]

Answer:

$y=\dfrac{1}{8}x^2+1$

Step-by-step explanation:

Since the vertex is right between the vertex and the directrix, the y value of the vertex must be (3+(-1))/2=1. The x coordinate will just be the same as that of the focus, or in this case 0. This means that the vertex will be at (0,1). Since the graph opens toward the focus, it will be opening up, and since its vertex is at (0,1), it will have an equation of:

$y=\dfrac{1}{8}x^2+1$

Hope this helps!

3 0

4 years ago

PLS HELP what would be the equation for this one?

____ [38]

Answer:

x^2 + y^2 = 25

Step-by-step explanation:

The standard form of a circle equation is:

(x - h)^2 + (y - k)^2 = r^2

where (h, k) is the center and r is the radius.