Question

Subtract the sum of (5^3 + 7^2 − 9) and (7 + 3^2 ) from the sum of (5^3 + 6) and (10^2 − 12)

Answer 1

Given:

Subtract the sum of $(5^3 + 7^2-9)$ and $(7 + 3^2)$ from the sum of $(5^3 + 6)$ and $(10^2-12)$.

To find:

The simplified value for the given statement.

Solution:

The sum of $(5^3 + 7^2-9)$ and $(7 + 3^2)$

$Sum_1=5^3+7^2-9+7 + 3^2$

$Sum_1=125+49-9+7 + 9$

$Sum_1=181$

The sum of $(5^3 + 6)$ and $(10^2-12)$.

$Sum_2=5^3 + 6+10^2-12$

$Sum_2=125+6+100-12$

$Sum_2=219$

Now, subtract $Sum_1$ from $Sum_2$.

$219-181=38$

Therefore, the required value after the subtraction is 38.