We would need to look over the z table to find the area under the standard normal distribution curve to the left of z = 1.04. Then we'll subtract it from 1 to get the proportion of a normal distribution corresponding to z scores greater than 1.04.
By looking at the z table, we can see that the area to the left of z = 1.04 is 0.8508. So the proportion of a normal distribution to the right of z = 1.04 is 1 – 0.8508 = 0.1492.
The answer is 0.1492.
Answer: n=-28
Step-by-step explanation:
<u>Answer:</u>
<u>Step-by-step explanation:</u>
<u>Write the product:</u>
<u>Convert it to improper fraction:</u>
<u>Multiply:</u>
<u>Simplify:</u>
Hence, <u>the product is 21/32.</u>
Hoped this helped.
1/6^3 is also equivalent to 6^-3. It can be reverted back to 1/216. Answers on ed2020 are A. and D.
