Answer:
Step-by-step explanation:
it's ambiguous.
where do we replace the y values in either a or b?
kindly, write down the question well.
Answer:
Step-by-step explanation:
產品 1 14 20 13
產品 2 15 11 18
產品 3 12 15 16
Answer:
x^2 -8x -5 = -3
x^2 -8x -2 = 0
We complete the square by:
1) Moving the "non X" term to the right:
x^2 -8x = 2
2) Dividing the equation by the coefficient of X²
The coefficient of x is 1 so we don't do anything
3) Now here's the "completing the square" stage in which we:
• take the coefficient of X
that is -8
• divide it by 2
-8 ÷ 2 = -4
• square that number
-4*-4 = 16
• then add it to both sides of the equation.
x^2 -8x +16 = 2 +16
That becomes
(x -4)^2 = 18
we take the square root of both sides:
(x -4) = sqr root (18)
x1 = sqr root (18) +4
AND
(x+4) = sqr root (18) -4
x1 = sqr root (18) +4 = 4.2426406871 + 4 = 8.2426406871
x2 = sqr root (18) -4 = = 4.2426406871 - 4 = .2426406871
Step-by-step explanation:
We can see that revolving the region formed by intersecting 3 lines, we will get 2 cones that are connected their bases.
Volume of the cone V=1/3 *πr²*h
1) small cone has r=5, and h=5
Volume small cone V1= 1/3 *π*5²*5 = 5³/3 *π
2) large cone has r=5, and h=21-6=15, h=15
Volume large cone V2= 1/3 *π*5²*15 = 5³*π
3) whole volume
5³/3 *π + 5³*π=5³π(1/3+1)=((5³*4)/3)π=(500/3)π≈166.7π≈523.6
Area
we see 2 right triangles,
Area of the triangle=1/2*b*h, where b -base, h -height
1) small one, b=5, h=5
A1=(1/2)*5*5=25/2
2)large one, b=5, h=15
A2=(1/2)*5*15=75/2
3)
whole area=A1+A2=25/2+75/2=100/2=
50
Answer:
A.(-2, 0)
C. (-1.4)
Step-by-step explanation:
we know that
If a point lie on the line, then the point must satisfy the equation of the line (makes the equation true)
we have

subtract 7 both sides


divide by 2 both sides

Substitute the value of x and the value of y of each point in the linear equation and analyze the result
<u><em>Verify each point</em></u>
case A) we have
(-2, 0)
For x=-2, y=0
substitute

---> is true
so
the point lie on the line
case B) we have
(1, 3)
For x=1, y=3
substitute

---> is not true
so
the point not lie on the line
case C) we have
(-1, 4)
For x=-1, y=4
substitute

---> is true
so
the point lie on the line
case D) we have
(1, -4)
For x=1, y=-4
substitute

---> is not true
so
the point not lie on the line
case E) we have
(0, -1)
For x=0, y=-1
substitute

---> is not true
so
the point not lie on the line