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3 years ago

Evaluate each expression when y = 5. a 12+ 4 b. 4(+3)

Mathematics

1 answer:

kati45 [8]3 years ago

5 0

Answer:

Step-by-step explanation:

it's ambiguous.

where do we replace the y values in either a or b?

kindly, write down the question well.

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(3x+4)^2=14 what are the solutions?

kherson [118]

$\bf (3x+4)^2=14\implies \sqrt{(3x+4)^2}=\pm\sqrt{14}\implies 3x+4=\pm\sqrt{14}
\\\\\\
3x=\pm \sqrt{14}-4\implies x=\cfrac{\pm \sqrt{14}-4}{3}\implies x=
\begin{cases}
\cfrac{\sqrt{14}-4}{3}\\\\
\cfrac{- \sqrt{14}-4}{3}
\end{cases}$

7 0

3 years ago

What is the length and width of a rectangle if Area is 20 and perimeter is 20

Anna [14]

Answer: a=5+√5

b=5-√5

Step-by-step explanation:

a=?

b=?

P=20

A=20

P=a*b=20

A=a+b=20

------------------

ab=20

a+b=10

--------

a=10-b

(10-b)b=20

-b²+10b-20=0

b=-10±√100-80/-2

b=-10±√20/-2

b=-10±2√5/-2

b=-10-2√5/-2=5+√55

b=5-√5

a+b=10

a+5-√5=10

a=5+√5

a+5+√5=10

a=5-√5

3 0

3 years ago

A company receives an order for 1,710 spoons. There are 18 spoons in each package shipped. How many packages will the company sh

Aleksandr-060686 [28]

The answer is 95 spoons. What you have to do is divide. You have to do 1710 Divided By 18, and your answer will be 95. Hope that helps.
~Silver

6 0

3 years ago

Suppose x and y are nonzero vectors in an inner product space. Show that x and y are orthogonal if and only if ||x+y|| = ||x-y||

harkovskaia [24]

Answer:

Step-by-step explanation:

Suppose x and y are nonzero vectors in an inner product space.

Let us assume that x and y are orthogonal

i.e. innter product is 0.

This implies dot product of x and y is 0

Then x.y =0

i.e. $x^2+y^2 +2x.y = x^2+y^2-2x.y\\||x+y||=||x-y||$

Proved

Converse part:

Let $||x+y||=||x-y||$

Square also would be equal

$||x+y||^2=||x-y||^2\\||x||^2+||y||^2+2x,t=||x||^2+||y||^2-2x.y\\x.y =0$

Hence inner product of x and y is 0

7 0

3 years ago

4m2 - 3mm + 5m4<br> help??

Alina [70]

Answer:

612mm I believe

5 0

3 years ago