Answer:
public class Main
{
public static void main(String[] args) {
minMax(1, 2, 3);
minMax(100, 25, 33);
minMax(11, 222, 37);
}
public static void minMax(int n1, int n2, int n3){
int max, min;
if(n1 >= n2 && n1 >= n3){
max = n1;
}
else if(n2 >= n1 && n2 >= n3){
max = n2;
}
else{
max = n3;
}
if(n1 <= n2 && n1 <= n3){
min = n1;
}
else if(n2 <= n1 && n2 <= n3){
min = n2;
}
else{
min = n3;
}
System.out.println("The max is " + max + "\nThe min is " + min);
}
}
Explanation:
*The code is in Java.
Create a function named minMax() that takes three integers, n1, n2 and n3
Inside the function:
Declare the min and max
Check if n1 is greater than or equal to n2 and n3. If it is set it as max. If not, check if n2 is greater than or equal to n1 and n3. If it is set it as max. Otherwise, set n3 as max
Check if n1 is smaller than or equal to n2 and n3. If it is set it as min. If not, check if n2 is smaller than or equal to n1 and n3. If it is set it as min. Otherwise, set n3 as min
Print the max and min
Inside the main:
Call the minMax() with different combinations
