Answer:
See explaination
Explanation:
MinMax.java
import java.util.*;
public class MinMax
{
static void MinMax(int[] arr)
{
int Min=arr[0]; // initializinf min and max with 1st value of array
int Max=arr[0];
for(int i=0;i<arr.length;i++) // iterating loop only once
{
if(arr[i]>Max) // checking max value
{
Max=arr[i];
}
if(arr[i]<Min) // checking min value
{
Min=arr[i];
}
}
System.out.println("Min Number is "+Min); //printing min value
System.out.println("Max Number is "+Max); //printing max value
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter N value: "); // taking n value
int n=sc.nextInt();
int[] arr=new int[n];
System.out.println("Enter N elements:"); // taking n elements into array
for(int i=0;i<n;i++)
{
arr[i]=sc.nextInt(); // each element into the array
}
MinMax(arr); // calling MinMax() method.
}
}
I believe that the option among these that is an Internet job search "do" is to pay attention to all directions before responding to job postings. You should be aware that you are never safe on the Internet, so be very careful.
Answer:
Following are the solution to this question:
Explanation:
Please find the complete question in the attached file.
It will obtain as much information about this matter as necessary even before the conference. It includes its gravity or probability of risk, various cases in the entire event, the possible solutions to the issues, as well as the consequences for parties involved in each potential answer, and Only at conferences, it may clarify to my boss that the explanation for the problem and also in details. It will be doing everything possible and try not to conceal the details but highlight the problem.
