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MArishka [77]
3 years ago
9

Joe is 4 years older than 2 times sam's age. the sum of their age is 25. find their ages

Mathematics
1 answer:
ad-work [718]3 years ago
7 0

Answer:

See Down

Step-by-step explanation:

When solving algebraic word problems, we usually assign the variable to the standard of comparison.  In this case, the standard of comparison is the age of Tom, so  

Let x = Tom's age.  Then

"4 less than twice the age of Tom" translates to 2x - 4.

The sum of their ages is 41, so

x + 2x - 4 = 41

Simplifying,

3x - 4 = 41

3x = 45

x = 15

Therefore, Tom is 15, Joe is 2(15) - 4 = 26

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Illusion [34]

Answer:

The right answer is:

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Step-by-step explanation:

Given:

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then,

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(a)

P (all gearboxes fit properly) = P(x=0)

                                               = \frac{\binom{7}{0} \binom{17}{5}}{\binom{24}{5}}

                                               = 0.1456

(b)

According to the question,

X = 91+5

Mean will be:

⇒ \mu = E(x)

       =E(91+5)

       =9E(1)+5

       =9.\frac{nr}{N}+5

       =9.\frac{5.7}{24} +5

       =18.125

Variance will be:

⇒ \sigma^2=Var(X)

         =V(9Y+5)

         =81.V(Y)

         =81.n.\frac{r}{N}.\frac{N-r}{N}.\frac{N-n}{N-1}

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2 years ago
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KATRIN_1 [288]

Answer:

x = -5

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Step-by-step explanation:

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