9514 1404 393
Answer:
Step-by-step explanation:
There are a couple of ways to work a problem like this. You have probably been taught to write equations for each of the payment amounts as a function of time, then equate those values to solve for the time that makes them equal.
at dealer 1, the total amount paid (y) will be a function of months (x):
y = 2500 +150x
at dealer 2, the corresponding equation is ...
y = 3000 +125x
These are equal when ...
y = y
2500 +150x = 3000 +125x
25x = 500 . . . . . . . . . subtract 125x +2500 from both sides
x = 500/25 = 20
The total paid will be the same after 20 months.
That amount is ...
y = 2500 +150(20) = 5500
$5500 will be paid to either dealer after 20 months.
__
The other way to work the problem is to "cut to the chase". The difference in down payment is made up at the rate of difference in monthly payments. So The number of monthly payments (x) required to equal the difference in down payments is ...
25x = 500 . . . . . . . . . you may recognize this equation from above
x = 500/25 = 20
Answer:
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
6
2
−
5
−
4
=
0
6x^{2}-5x-4=0
6x2−5x−4=0
=
6
a={\color{#c92786}{6}}
a=6
=
−
5
b={\color{#e8710a}{-5}}
b=−5
=
−
4
c={\color{#129eaf}{-4}}
c=−4
=
−
(
−
5
)
±
(
−
5
)
2
−
4
⋅
6
(
−
4
)
√
2
⋅
6
Step-by-step explanation:
You could just subtract it or you could make it into a plus negative
Answer:
Brand 2 is the better deal
Step-by-step explanation:
Answer:
...Which is the required Equation.
Step-by-step explanation:
Question is
Translate this sentence into an equation
28 is the product of Julie score and two.
Solution:
Let the Julie score denoted by 'x'
According to the given condition,
28 is the product of Julie score and two
i.e 28 = 'x' × 2
![28=x\times 2\\\\2x=28](https://tex.z-dn.net/?f=28%3Dx%5Ctimes%202%5C%5C%5C%5C2x%3D28)
...Which is the required Equation.