All categories

3 years ago

Using the GCF factor the given expression: 4m - 20

Mathematics

1 answer:

nirvana33 [79]3 years ago

7 0

Answer:

The first and second one

Step-by-step explanation:

4(m-5)=4*m-4*5=4m-20

2(2m-10)=2*2m-2*10=4m-20

You might be interested in

A random sample of 100 teletype operators indicates that their salaries fluctuate quite a bit. The sample Standard deviation of

ELEN [110]

Answer:

$\frac{(99)(10)^2}{123.225} \leq \sigma^2 \leq \frac{(99)(10)^2}{77.046}$

$80.341 \leq \sigma^2 \leq 128.495$

Now we just take square root on both sides of the interval and we got:

$8.963 \leq \sigma \leq 11.336$

Step-by-step explanation:

Data given and notation

s=10 represent the sample standard deviation

$\bar x$ represent the sample mean

n=100 the sample size

Confidence=90% or 0.90

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=100-1=99$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical values.

The excel commands would be: "=CHISQ.INV(0.05,99)" "=CHISQ.INV(0.95,99)". so for this case the critical values are:

$\chi^2_{\alpha/2}=123.225$

$\chi^2_{1- \alpha/2}=77.046$

And replacing into the formula for the interval we got:

$\frac{(99)(10)^2}{123.225} \leq \sigma^2 \leq \frac{(99)(10)^2}{77.046}$

$80.341 \leq \sigma^2 \leq 128.495$

Now we just take square root on both sides of the interval and we got:

$8.963 \leq \sigma \leq 11.336$

5 0

3 years ago

Lin created a scaled copy of Triangle A with an area of 72 square units. How many times larger is the area of the scaled copy co

Tju [1.3M]

Answer:

Copy's area is 16 times bigger then triangle area.

Step-by-step explanation:

Given:

Area of copy = 72 unit²

Find:

How bigger copy compared to triangle

Computation:

Area of triangle = [1/2][base][height]

Area of triangle = [1/2][3][3]

Area of triangle = 4.5 unit²

So.

Area of copy / Area of triangle

72 / 4.5

So,

Copy's area is 16 times bigger then triangle area.

3 0

3 years ago

Which statement is true about the potential solution x = –5? This number is not a true solution because it is negative. This num

podryga [215]

Answer:

the correct option is d on edg. Hope i helped:)

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

Round48.073 to the nearest hundredth

Hunter-Best [27]

Answer:

48.07 (brainliest answer?)

Step-by-step explanation:

'7' is the hundredth figure

3 is not 5 or over so it stays the same

5 0

3 years ago

Read 2 more answers

Cindy takes out an $8,000 loan to buy a camper. The lowest simple interest rate she

maks197457 [2]

The answer is 9,274$ what you do is

1. 8,000+3%=8,240
2. 8,240+3% of 8,240 and so on so forth so basically what you do is take 3% of the last sum and add that to get the new sum

7 0

4 years ago