The answer I came up with is 00934
For
solving system of equations, we can use either substitution where we plug one
equation into the other, or elimination where we combine the equations.
-
Using elimination,
you would to eliminate one variable from both equations, so you automatically would
get one equation with one variable!
- Using
substitution
means you are going to solve one equation for one variable and substitute with
its value in the other equation in order to get also an equation with one
variable.
Let's take an example ...
y+x=2 and y-2x = 1
<span>Using <span>elimination, we need to subtract these two equation; one from the other...
y+x=2
-
y-2x=1
-----------
0+3x=1
then
x=1/3 and then substitute into any equation to get y-value</span></span>
y+x=2
y+1/3 = 2 >>>>>
y=5/3NOW...<span>Using substitution
</span>y+x=2 and y-2x = 1 >>(y=1+2x)
Plug (y=1+2x) into y+x=2 and solve for x
y+x=2
(1+2x) + x =2
1+3x = 2
3x=1
again (and for sure)
x = 1/3plug in x=1/3 into any of the equations above to get y:
y+x=2
y+1/3=2
y=5/3DOne !!!!!!
I hope you got
the idea
If you still need help, just let me know.
Answer: b = -6, 4
Step-by-step explanation:
Convert into factored form :
(b+6)(b-4)
Then make one of the terms 0.
From right triangle trigonometry, we have the following:
,
where the "opposite side" means the opposite side to angle with measure
, and "adjacent side" means the adjacent side to angle with measure
.
is a constant which can be found using a calculator.
In the calculator of the pc press: view - scientific - 35 - tan.
This gives
Thus, back in the equation
we substitute as follows and solve:
Answer: 8.4 cm
Answer:
<20,23>
Step-by-step explanation:
u= <4,5> and v= <0,-1>
2v = 2*<0,-1> = <0,-2>
5u = 5* <4,5> = <20,25>
2v+5u = <0,-2> + <20,25>
= <20,23>
