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trasher [3.6K]
3 years ago
6

Which is the greater rate? 6 points in 3 attempts 15 points in 5 attempts

Mathematics
1 answer:
Digiron [165]3 years ago
3 0

Answer:

15 points in 5 attempts

Step-by-step explanation:

I don't see the proble to solve so I based it on what you wrote

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if a snowball rolls down a hill and its surface area increaces at a rate of 18cm^2/min, find the rate at which the radius increa
sp2606 [1]

Answer: dr/dt = 9/(24pi)  cm per minute

9/(24pi) is approximately equal to 0.119366

=============================================

Work Shown:

Given info

dS/dt = 18 cm^2/min is the rate of change of the surface area

r = 6 cm is the radius, from the fact that the diameter is 12 cm

--------

Use the surface area equation given, apply the derivative, plug in the given values and then isolate dr/dt which represents the rate of change for the radius

S = 4*pi*r^2

dS/dt = 2*4*pi*r*dr/dt

dS/dt = 8*pi*r*dr/dt

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