Answer:
D. 30 sq in.
Step-by-step explanation:
10+9+6+5=30 sq in.
This is how the sketch should look on your graph!
Answer:
Perimeter is 9x² + 15x + 36
Step-by-step explanation:
- p is the perimeter
- s is side
3(110+160) 3 days each say has 110+160 students
<span>A. 8 wreaths, 6 trees, 2 sleighs
Nothing much to do for this problem except to try each option and see if it meets the constraints of available time. So let's check them out.
A. 8 wreaths, 6 trees, 2 sleighs
prep = 8 * 3 + 6 * 14 + 2 * 4 = 116 hours.
paint = 8 * 2 + 6 * 3 + 2 * 15 = 64 hours.
fire = 8 * 9 + 6 * 4 + 2 * 7 = 110 hours.
All three values are less than or equal to the constraints of 116, 64, and 110.
This option will work.
B. 6 wreaths, 2 trees, 8 sleighs
prep = 6 * 3 + 2 * 14 + 8 * 4 = 78 hours.
paint = 6 * 2 + 2 * 3 + 8 * 15 = 138 hours.
138 is more than the allowed 64, can't do this option.
Don't bother to calculate how many hours of firing needed.
C. 9 wreaths, 7 trees, 3 sleighs
prep = 9 * 3 + 7 * 14 + 3 * 4 = 137 hours.
137 is more than the allowed 116, can't do this option.
Don't bother to calculate how many hours of painting or firing needed.
D. 2 wreaths, 8 trees, 6 sleighs
prep = 2 * 3 + 8 * 14 + 6 * 4 = 142 hours.
142 is more than the allowed 116, can't do this option.
Don't bother to calculate how many hours of painting or firing needed.
Of the 4 choices available, only option "A" falls under the required time constraints.</span>
