Answer:
The object's velocity at t = 7 is -16 ft/s
The maximum height is 832 ft and it occurs when 
Step-by-step explanation:
From the information given, the equation of motion of the object is
For any equation of motion s(t), the instantaneous velocity at time t is given by
(a) To find the object's velocity at t = 7, you must:
Next, we evaluate when t = 7
The object's velocity at t = 7 is -16 ft/s
(b) <em>To find the maximum of a function we always use the derivative of the function and we set it equal zero to find the</em><em> critical points.</em>
To find the maximum height and when it occurs, we set the velocity function equal to 0 and solve for t.
Next, we substitute this value into the equation of motion to find the maximum height
The maximum height is 832 ft and it occurs when
Answer:
D = 59t
P = 42t
5 hours after noon, darmian is 17 miles closer to the stadium than paisley
Step-by-step explanation:
At noon, Damian is 383 miles away from the stadium and paisley is 315 miles away from the stadium.
Now, we are told that damians speed is 59 mph while paisley's speed is 42 mph.
At t hours after noon, their distance covered will be;
Damian; D = 59t
Paisley; P = 42t
This is because distance = speed × time
Now, 5 hours after noon, their respective distance covered will be;
D(5) = 59 × 5 = 295 miles
P(5) = 42 × 5 = 210 miles
This means that;
distance of Damian from the stadium is; 383 - 295 = 88 miles
Distance of paisley from the stadium is;
315 - 210 = 105 miles
Difference in their distances to the stadium = 105 - 88 = 17 miles
Thus, 5 hours after noon, darmian is 17 miles closer to the stadium than paisley
Answer:
$666
Step-by-step explanation:
I think you just need to do 2664×0.25 ( which you can do it on a calculator ) , is
<u><em>$666</em></u>
Hence option a I believe is true
