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const2013 [10]
4 years ago
14

An NBA basketball court is rectangular in shape where the length is 2m less than twice the width. If the perimeter of the court

is 86m, what are the dimensions (length and width) of the court?
Mathematics
1 answer:
yarga [219]4 years ago
3 0

Answer:

Length = 28 m

Width = 15 m

Step-by-step explanation:

Court is rectangular in shape.

Now, we are told that;

Length is 2m less than twice the width(W) .

Thus;

Length; L = 2W - 2

We are told the perimeter is 86 m.

Formula for perimeter of a rectangle is;

P = 2(L + W)

Thus;

2((2W - 2) + W) = 86

Divide both sides by 2 to get;

(2W - 2) + W = 43

3W - 2 = 43

3W = 43 + 2

3W = 45

W = 45/3

W = 15 m

Thus; L = 2(15) - 2

L = 30 - 2

L = 28 m

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