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lara [203]
3 years ago
5

Which expression is equivalent to 76× + 68​

Mathematics
2 answers:
Naily [24]3 years ago
8 0

Answer:

4(19x+17)

Step-by-step explanation:

kap26 [50]3 years ago
4 0

Answer:

You can just switch them around, 68 + 76×

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What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success​ p? C
charle [14.2K]

Answer:

(D)E[ X ] =np.

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success​ p,

f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq  x\leq n

E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}

Now,

x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)

Substituting,

E(X)=\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^x(1-p)^{n-x}

Factoring out the n and one p from the above expression:

E(X)=np\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^{x-1}(1-p)^{(n-1)-(x-1)}

Representing k=x-1 in the above gives us:

E(X)=np\sum_{k=0}^{n}n\left(\begin{array}{c}n-1\\k\end{array}\right)p^{k}(1-p)^{(n-1)-k}

This can then be written by the Binomial Formula as:

E[ X ] = (np) (p +(1 - p))^{n -1 }= np.

5 0
4 years ago
Twice the difference of a number and 9 equals 5.
emmasim [6.3K]

Answer:

7

Step-by-step explanation:

if the number is x then you know 2x-9=5

2x=14

x=7

so the number is 7

8 0
3 years ago
1 1/9 • 6= x what is x
brilliants [131]
This problem basically already gives you X, you just have to simplify.

To complete this problem all you have to do is divide 11 by 9.6

11 / 9.6 = 1.15

So X = 1.15
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3 years ago
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A quickie. If n identical dice are rolled, number of possible outcomes are?
nata0808 [166]
In rolling one die, there are 6 possible outcomes because each die has 4 faces. The number of outcomes when rolling n dice is equal to 6^n. By this, the number of outcomes when 2 dice are rolled is 36, 216 for 3 dice, and so on. 
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4 years ago
A car is traveling at 60 kilometers per hour. How many kilometers<br> does the car cover in 7 hours?
IgorC [24]
That would be 420 kilometers in total
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4 years ago
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