A4 means the 4th number so it would be 17.
Answer:
7
Step-by-step explanation:
This is a Poisson distribution problem with the formula;
P(x;μ) = (e^(-μ)) × (μ^(x))/x!
We are told that the grocer sells three of a certain article per week. Thus;
μ = 3
Now, we want to find out How many of these should he have in stock so that the chance of his running out within a week is less than 0.01.
This means;
P(X > k) < 0.01
This can be rewritten as;
P(X ≤ k) < 0.99
Let's try x = 8
P(8;3) = (e^(-3)) × (3^(8))/8!
P(8;3) = 0.008
But; P(X ≤ 8) = 1 - 0.008 = 0.992
This is more than 0.99 and thus is not the answer
Let's try x = 7
P(7;3) = (e^(-3)) × (3^(7))/7!
P(7;3) = 0.022
But; P(X ≤ 7) = 1 - 0.022 = 0.978
Thus is less than 0.99.
Thus, stock should be 7
Answer: here the answer
Step-by-step explanation:
Answer:
Step-by-step explanation:
1) 2 - (- 8) = 2 + 8 = 10
2) 2/5 + (- 1/5) = 2/5 - 1/5 = 1/5
3) We can find the common denominators through the least common multiple between the denominators:
4,12 | 2
2, 6 | 2
1, 3 | 3
1, 1 (2 × 2 × 3 = 12)
Then, 12 is the least common denominator.
4) 8 (1/4) + 10 (2/5) + 7 (5/8)
8 (1/4) = 4/4 + 4/4 + 4/4 + 4/4 + 4/4 + 4/4 + 4/4 + 4/4 + 1/4 = 33/4
10 (2/5) = 5/5 + 5/5 + 5/5 + 5/5 + 5/5 + 5/5 + 5/5 + 5/5 + 5/5 + 5/5 + 2/5 = 52/5
7 (5/8) = 8/8 + 8/8 + 8/8 + 8/8 + 8/8
+ 8/8 + 8/8 + 5/8 = 61/8
33/4 + 52/5 + 61/8
Employing the least common denominator:
4, 5, 8 | 2
2, 5, 4 | 2
1, 5, 2 | 2
1, 5, 1 | 5
1, 1, 1 (2 × 2 × 2 × 5 = 40)
(40 ÷ 4 × 33)/40 + (40 ÷ 5 × 52)/40 + (40 ÷ 8 × 61)/40
330/40 + 416/40 + 305/40
1051/40
This person ran about 26 Miles
I hope I helped you.
Answer:
B.
Step-by-step explanation:
