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Debora [2.8K]
3 years ago
5

There are 56 students in a school play. The ratio of boys to girls is 3:5. How many girls are in the school play?

Mathematics
1 answer:
Murrr4er [49]3 years ago
5 0

Answer:

35 girls

Step-by-step explanation:

First add the ratios together ( 3+5) this will give you 8. Then divide the total number of students by 8, this will get you 7. Now multiply 7 to 3 and multiply 7 to 5. As the ratio of boy to girl is 3 to 5, to find how many girls are in the school play we multiply 7 to 5. This makes 35 girls.

If you want to check, 7 x 3 =21 boys and 7 x 5=35 girls. 35 +21= 56 (the total number of students).

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3 0
3 years ago
Write the equation of a line that is perpendicular to y = -0.3z +6 and that passes through the point
lawyer [7]

Answer:

y = 3.33x - 18

Step-by-step explanation:

In order for a line to be perpendicular to another, it must have a slope with the negative reciprocal

  • Here in the equation y = -0.3z + 6 has a slope of  -0.3 (can also be written as -\frac{3}{10})
  • A line that is perpendicular to this line will need to have a slope of 3.33 repeating (or \frac{10}{3})
  • I will using fractions for simplicity and convert to decimals afterwards

Since we have our slope and the two points, we can plug them into y = mx + b to solve for b and write our new equation of a line

  • Substituting in the values that we have we get: -8=\frac{10}{3}(3)+b
  • Simplifying we get -8 = 10 + b, making b = -18

Now that we have our slope and our y-intercept we can plug them into the same formula used before to find our perpendicular line:

  • y= \frac{10}{3}x-18 which can also be written as y = 3.33x - 18

5 0
3 years ago
What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (−4,
zheka24 [161]
Answer: C ) y + 3 = 1/4 ( x + 4 )

Explanation:

Given that you did not include the "given line", I can help you by explaning how to solve this kind of problems, step by step.

The procedure is based of the property of perpendicular lines: the product of the slopes of perpedicular lines is negative 1.

If you call m1, the slope of a line and m2 the slope of a perpendicular line, then:

m1 * m2 = - 1, and you can solve for either m1 or m2:

m1 = - (1 / m2)

m2 = - (1 / m1).

With that this is the procedure:

1) find the slope of the "given line". Name it m1.

2) find the slope of the perpendicular line:

    m2 = - (1 / m1).

3) Use the equation of the line with the point (x1,y1) and slope m2

y - y1
-------- = m2
x - x1

4) In this case the point is (-4, - 3)=> x1 = - 4, y1 = - 3

=>

y - (-3)
---------= m2
x - (-4)

=> y + 3 = m2 * (x + 4)

=> y = m2*x + m2 * 4 - 3

Which is the point-slope form. You only have to replace m2 with the slope value of the perpendicular line, which I already explained that you find as m2 = (-1/m1).

Taking that the other line has m1 = - 4 so m2 = 1/4

      y = (1/4)x + (1/4) * 4 - 3

      y = (1/4) (x +4) - 3

      y + 3 = (1/4) (x + 4) and answer is: C ) y + 3 = 1/4 ( x + 4 )



7 0
3 years ago
Read 2 more answers
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insens350 [35]

Answer:

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Step-by-step explanation:

Assuming your x'y' is xy with the variables to the first power, that is the term with the smallest x- and y-exponents. It is a factor of all the other terms so is the <em>greatest common factor</em> of all the terms.

8 0
3 years ago
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Ugo [173]
The answer is 4y^4.

Comment if you want me to explain.

4 0
3 years ago
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