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noname [10]
3 years ago
8

Please use the following image for the next 7 questions. Keep in mind

Mathematics
1 answer:
ziro4ka [17]3 years ago
4 0

Answer:

Step-by-step explanation:

1). Since, XM is the radius of the circle,

   Therefore, area of the circle = \pi r^{2}

                                                   = \pi (XM)^2

                                                   = \pi (12)^2

                                                   = 452.39 units²

2). Circumference of a circle = 2πr

                                                = 2π(XM)

                                                = 2π(12)

                                                = 24π

                                                = 75.40 units

3). By applying Pythagoras theorem in ΔYXM,

    YM² = XY² + XM²

    (43)²= (XY)² + (12)²

     1849 - 144 = (XY)²

     XY = 41.29 units

4). tan(∠M) = \frac{\text{Opposite side}}{\text{Adjacent side}}

                  = \frac{XY}{XM}

    m∠M = tan^{-1}(\frac{41.29}{12} )

              = 73.79°

5). Area of ΔXYM = \frac{1}{2}(\text{Base)}(\text{Height})

                             = \frac{1}{2}(41.29)(12)

                             = 247.74 square units

6). Area of the minor sector created by ΔXYM = \frac{\theta}{360}(\pi r^2)

                                                                             = \frac{73.79}{360}(452.39)

                                                                             = 92.73 units²

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20 points!<br> I need help (asap!!)
EastWind [94]

Answer:

<h2>x = 5</h2><h2>OB = 36</h2><h2>BE = 54</h2>

Step-by-step explanation:

We know that the medians of the triangle divides in a ratio of 2:1. Therefore we have the equation:

\dfrac{9x-9}{2x+8}=\dfrac{2}{1}                <em>cross multiply</em>

1(9x-9)=2(2x+8)             <em>use distributive property a(b + c) = ab + ac</em>

9x-9=(2)(2x)+(2)(8)

9x-9=4x+16                 <em>add 9 to both sides</em>

9x=4x+25                <em>subtract 4x from both sides</em>

5x=25             <em>divide both sides by 5</em>

\boxed{x=5}

OB=9x-9\to OB=9(5)-9=45-9=\boxed{36}

OE=OB:2\to OE=36:2=18\to BE=BO+OE\to BE=36+18=54


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