Distance of each track are:
D₁ = 428.5 yd
D₂ = 436.35 yd
D₃ = 444.20 yd
D₄ = 452.05 yd
D₅ = 459.91 yd
D₆ = 467.76 yd
D₇ = 475.61 yd
D₈ = 483.47 yd
<u>Explanation:</u>
Given:
Track is divided into 8 lanes.
The length around each track is the two lengths of the rectangle plus the two lengths of the semi-circle with varying diameters.
Thus,

Starting from the innermost edge with a diameter of 60yd.
Each lane is 10/8 = 1.25yd
So, the diameter increases by 2(1.25) = 2.5 yd each lane going outward.
So, the distances are:
D₁ = 240 + π (60) → 428.5yd
D₂ = 240 + π(60 + 2.5) → 436.35 yd
D₃ = 240 + π(60 + 5) → 444.20 yd
D₄ = 240 + π(60 + 7.5) → 452.05 yd
D₅ = 240 + π(60 + 10) → 459.91 yd
D₆ = 24 + π(60 + 12.5) → 467.76 yd
D₇ = 240 + π(60 + 15) → 475.61 yd
D₈ = 240 + π(60 + 17.5) → 483.47 yd
We know that the sum of measures of internal angles in each quadrangle is 360°.
Look at the picture.

Therefore we have:

Answer: θ = 141 deg.
Answer:
Subtract 80 from 83 . The result of division of 8310 is 8 with a remainder of 3 .
Given:
line C: y = x + 14
line D: y = 3x + 2
(6,20) or (3,11)
line C: y = 6 + 14 = 20 or y = 3 + 14 = 17
line D: y = 3(6) + 2 = 18 + 2 = 20 or y = 3(3) + 2 = 9 + 2 = 11
(6,20), because both lines pass through this point.
When 1 is added to another 1 they join together to form a 2. Bruh idk what 1+1 long method is. But I hope it helped.