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GrogVix [38]
3 years ago
5

The scores on an exam are normally distributed, with a mean of 75 and a standard deviation of 5. What percent of the scores are

less than 80?
A. 50%
B. 84%
C. 13.5%
D. 16%
Mathematics
1 answer:
stellarik [79]3 years ago
5 0

Answer:

B. 84%

Step-by-step explanation:

Given

Mean= π=75

Standard Deviation= σ=5

As we have to calculate the percentage of score less than 80, we will find the z-score of 80

z=(x-μ)/σ

=  (80-75)/5

=5/5

=1

The z-score table value for 1 is 0.8413.

For converting this value into percentage, the value will be multiplied by 100.

So,

Percentage of students whose score is less than 80 = 0.8413*100

=84.13%

Rounding off gives us : 84%

So option B is the correct answer..

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An integer is 5 more than 4 times another. If the product of the two integers is 51, then find the integers.
Yakvenalex [24]

Answer:

  • <u>3 </u><u>and</u><u> 17</u> are required integers

Step-by-step explanation:

  • Let one integer be x
  • And other integer be y

x = 4y + 5

xy = 51

<u>According to </u><u>question </u><u>:</u>

➞ (4y + 5)y = 51

➞ 4y² + 5y = 51

➞ 4y² + 5y - 51 = 0

➞ 4y² + 17y - 12y - 51 = 0

➞ y (4y + 17) - 3(4y + 17) = 0

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Hence,

➞ <u>y = 3</u>

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➞ x = 4 (3) + 5

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Answer:

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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